如何解决 java.text.ParseException: Unparseable date？
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How to solve java.text.ParseException: Unparseable date?
提问by Woppi
I'm trying to convert this to a readable format however, keep getting java.text.ParseException: Unparseable date: "2016-11-18T11:13:43.838Z" (at offset 23)
我正在尝试将其转换为可读格式，但是，请继续获取 java.text.ParseException: Unparseable date: "2016-11-18T11:13:43.838Z" (at offset 23)
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ", Locale.US);
try {
Date date1 = df.parse("2016-11-18T11:13:43.838Z");
DateFormat outputFormatter1 = new SimpleDateFormat("dd-MMM-yyyy");
String output1 = outputFormatter1.format(date1); //
} catch (ParseException e) {
e.printStackTrace();
}
I read about adding locale as other SO answers suggested but it is still not working.
我阅读了有关按照其他 SO 答案的建议添加语言环境的内容，但它仍然无法正常工作。
回答by Manos Nikolaidis
According to the docsthe Zin your format string indicates an RFC 822 time zone e.g. +01:00. You need to parse a ISO 8601 Time zone (the Zin your input string indicating UTC timezone). You configure that with X:
根据该文档的Z在格式字符串表示RFC 822时区，例如+01：00。您需要解析 ISO 8601 时区（Z在您的输入字符串中指示 UTC 时区）。您可以使用X以下命令进行配置：
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSX", Locale.US);
回答by ΦXoc? ? Пepeúpa ツ
you are parsing a string that is not a correct representation of that pattern, you are missing the TimeZone... something like: -0600
您正在解析一个不是该模式的正确表示的字符串，您缺少时区...类似于： -0600
example:
例子：
Date date1 = df.parse("2016-11-18T11:13:43.838-0600Z");
here is the docfor more info....
这是有关更多信息的文档....
your code should look like:
您的代码应如下所示：
DateFormat df = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSZ");
try {
Date date1 = df.parse("2016-11-18T11:13:43.838-0600Z");
DateFormat outputFormatter1 = new SimpleDateFormat("dd-MMM-yyyy");
String output1 = outputFormatter1.format(date1); //
} catch (ParseException e) {
e.printStackTrace();
}
回答by Malte Hartwig
Reading the Javadoc for SimpleDateFormat, I found that using Zfor timezone is very strict. It will not recognize "Z"as zulu, it only accepts numeric timezone offsets.
You might want to try Xinstead, which accept "Z"according to the documentation.
阅读SimpleDateFormat的 Javadoc ，我发现使用Zfor timezone 非常严格。它不会识别"Z"为祖鲁语，它只接受数字时区偏移量。您可能想尝试X改为"Z"根据文档接受。
回答by Felix Cruz
Please try this format
请试试这个格式
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS");
