bash 非重复行数 - 唯一计数
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Number of non repeating lines - unique count
提问by john blackwood
Here is my problem: Any number of lines of text is given from standard input. Output: number of non repeating lines
这是我的问题：从标准输入给出任意数量的文本行。输出：非重复行数
INPUT:
输入：
She is wearing black shoes.
My name is Johny.
I hate mondays.
My name is Johny.
I don't understand you.
She is wearing black shoes.
OUTPUT:
输出：
2
回答by Ding
You could try using uniq man uniqand do the following
您可以尝试使用 uniqman uniq并执行以下操作
sort file | uniq -u | wc -l
回答by glenn Hymanman
Here's how I'd solve the problem:
这是我解决问题的方法：
... | awk '{n[... | {
declare -A count # count is an associative array
# iterate over each line of the input
# accumulate the number of times we've seen this line
#
# the construct "IFS= read -r line" ensures we capture the line exactly
while IFS= read -r line; do
(( count["$line"]++ ))
done
# now add up the number of lines who's count is only 1
num=0
for c in "${count[@]}"; do
if (( $c == 1 )); then
(( num++ ))
fi
done
echo $num
}
]++} END {for (line in n) if (n[line]==1) num++; print num}'
But that's pretty opaque. Here's a (slightly) more legible way to look at it (requires bash version 4)
但这很不透明。这是一种（稍微）更清晰的查看方式（需要 bash 版本 4）
##代码##