如何在 Java 中获取 unicode 字符的十进制值？
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How do I get the decimal value of a unicode character in Java?
提问by Mike Sickler
I need a programmatic way to get the decimal value of each character in a String, so that I can encode them as HTML entities, for example:
我需要一种编程方式来获取字符串中每个字符的十进制值，以便我可以将它们编码为 HTML 实体，例如：
UTF-8:
UTF-8：
著者名
Decimal:
十进制：
著者名
回答by Jon Skeet
I suspect you're just interested in a conversion from charto int, which is implicit:
我怀疑您只是对从charto的转换感兴趣int，这是隐式的：
for (int i = 0; i < text.length(); i++)
{
char c = text.charAt(i);
int value = c;
System.out.println(value);
}
EDIT: If you want to handle surrogate pairs, you can use something like:
编辑：如果你想处理代理对，你可以使用类似的东西：
for (int i = 0; i < text.length(); i++)
{
int codePoint = text.codePointAt(i);
// Skip over the second char in a surrogate pair
if (codePoint > 0xffff)
{
i++;
}
System.out.println(codePoint);
}
回答by Voo
Ok after reading Jon's post and still musing about surrogates in Java, I decided to be a bit less lazy and google it up. There's actually support for surrogates in the Character class it's just a bit.. roundabout
好吧，在阅读了 Jon 的帖子并仍在思考 Java 中的代理后，我决定不那么懒惰并用谷歌搜索它。实际上在 Character 类中支持代理，只是有点……迂回
So here's the code that'll work correctly, assuming valid input:
所以这里的代码可以正常工作，假设输入有效：
for (int i = 0; i < str.length(); i++) {
char ch = str.charAt(i);
if (Character.isHighSurrogate(ch)) {
System.out.println("Codepoint: " +
Character.toCodePoint(ch, str.charAt(i + 1)));
i++;
}
System.out.println("Codepoint: " + (int)ch);
}
