C语言 在 C 中使用 sigaction 启用信号处理程序
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Enable a signal handler using sigaction in C
提问by txs
struct sigaction psa;
I have enabled my signal handler in the main function as shown below:
我在主函数中启用了我的信号处理程序，如下所示：
memset (&psa, 0, sizeof (psa));
psa.sa_handler = pSigHandler;
sigaction (SIGALRM, &psa, NULL);
sigaction(SIGVTALRM, &psa, NULL);
sigaction(SIGPROF, &psa, NULL);
My signal handler is like this:
我的信号处理程序是这样的：
static void pSigHandler(int signo){
printf("Pareint signum: %d", signo);// debug
switch (signo) {
case SIGALRM:
printf("P SIGALRM handler");//debug
break;
case SIGVTALRM:
printf("P SIGVTALRM handler");//debug
break;
case SIGPROF:
printf("P SIGPROF handler");//debug
break;
default: /*Should never get this case*/
break;
}
return;
}
Now my question may be obvious to some people, why didn't I see the printed debug lines when I run this? In fact, nothing was printed. Thank you very much for helping me to understand this. I'm running it on Linux, used Eclipse to program.
现在我的问题对某些人来说可能很明显，为什么我在运行它时没有看到打印的调试行？事实上，什么都没有打印。非常感谢您帮助我理解这一点。我在 Linux 上运行它，使用 Eclipse 进行编程。
回答by Thomas Dignan
#include <stdio.h>
#include <signal.h>
static void pSigHandler(int signo){
switch (signo) {
case SIGTSTP:
printf("TSTP");
fflush(stdout);
break;
}
}
int main(void)
{
struct sigaction psa;
psa.sa_handler = pSigHandler;
sigaction(SIGTSTP, &psa, NULL);
for(;;) {}
return 0;
}
Because you need to fflush(stdout)
因为你需要 fflush(stdout)
try with C-z
试试 Cz
I'm not even sure if it's safe to use stdio in a signal handler though.
我什至不确定在信号处理程序中使用 stdio 是否安全。
Update: http://bytes.com/topic/c/answers/440109-signal-handler-sigsegv
更新：http: //bytes.com/topic/c/answers/440109-signal-handler-sigsegv
According to that link, you should not do this.
根据该链接，您不应该这样做。
