C语言：使用strtok()一次后如何获取剩余的字符串
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C language: How to get the remaining string after using strtok() once
提问by Eric Tseng
My string is "A,B,C,D,E"
And the separator is ","
How can I get the remaining string after doing strtok() once, that is "B,C,D,E"
我的字符串是 "A,B,C,D,E"
而分隔符是 ","
我怎样才能在做一次 strtok() 后得到剩余的字符串，即 "B,C,D,E"
char a[] = "A,B,C,D,E";
char * separator = ",";
char * b = strtok(a,separator);
printf("a: %s\n", a);
printf("b: %s\n", b);
The output is:
a: A
b: A
输出为：
a：A
b：A
But how to get the result
a: B,C,D,E
b: A
Thanks.
但是如何得到结果
a: B,C,D,E
b: A
谢谢。
回答by Neil
You can vary the set of delimiters, so simply pass an empty string:
您可以更改分隔符集，因此只需传递一个空字符串：
char a[] = "A,B,C,D,E";
char * separator = ",";
char * b = strtok(a, separator);
printf("b: %s\n", b);
char * c = strtok(NULL, "");
printf("c: %s\n", c);
回答by unwind
Don't use strtok()for this, since that's not what it's for.
不要strtok()用于此，因为那不是它的用途。
Use strchr()to find the first separator, and go from there:
使用strchr()查找第一个分离器，并从那里：
char a[] = "A,B,C,D,E";
const char separator = ',';
char * const sep_at = strchr(a, separator);
if(sep_at != NULL)
{
*sep_at = 'char a[] = "A,B,C,D,E";
char * end_of_a = a + strlen(a); /* Memorise the end of s. */
char * separator = ",";
char * b = strtok(a, separator);
printf("a: %s\n", a);
printf("b: %s\n", b);
/* There might be some more tokenising here, assigning its result to b. */
if (NULL != b)
{
b = strtok(NULL, separator);
}
if (NULL != b)
{ /* Get reference to and print remainder: */
char * end_of_b = b + strlen(b);
if (end_of_b != end_of_a) /* Test whether there really needs to be something,
will say tokenising did not already reached the end of a,
which however is not the case for this example. */
{
char * remainder = end_of_b + 1;
printf("remainder: `%s`\n", remainder);
}
}
'; /* overwrite first separator, creating two strings. */
printf("first part: '%s'\nsecond part: '%s'\n", a, sep_at + 1);
}
回答by alk
Try this:
尝试这个：
char a[] = "A,B,C,D,E";
const char *separator = ",";
char *b = strtok(a, separator);
while (b) {
printf("element: %s\n", b);
b = strtok(NULL, separator);
}
回答by Atle
strtokremembers the last string it worked with and where it ended. To get the next string, call it again with NULLas first argument.
strtok记住它使用的最后一个字符串以及它在哪里结束。要获取下一个字符串，请使用NULL第一个参数再次调用它。
char a[] = "A,B,C,D,E";
char *sep = strchr(a, ',');
*sep = '##代码##';
puts(a);
puts(sep + 1);
Note: This is not thread safe.
注意：这不是线程安全的。
回答by Fred Foo
If using strtokis not a requirement, you can use strchrinstead since the separator is a single character:
如果 usingstrtok不是必需的，您可以使用，strchr因为分隔符是单个字符：
回答by nav_jan
printf("a: %s\n", a+1+strlen(b));
printf("a: %s\n", a+1+strlen(b));
Try this
尝试这个
