ios 从“int”分配给“int *”的不兼容整数到指针转换
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/5293406/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Incompatible integer to pointer conversion assigning to 'int *' from 'int'
提问by Preston
I have yet another pesky warning I would like gone. Basically, I have an int declared like this: @property (nonatomic, assign) int *myInt;and set like this: myInt = 0;. It is also synthesized in the implementation file. I am getting a warning on the line where I set the int's value and it says Incompatible intiger to pointer conversion assigning to 'int *' from 'int'.What should I do to fix this?
我还有另一个讨厌的警告，我想离开。基本上，我有一个像这样声明的 int:@property (nonatomic, assign) int *myInt;并像这样设置：myInt = 0;。它也在实现文件中综合。我在设置 int 值的行上收到警告，它说Incompatible intiger to pointer conversion assigning to 'int *' from 'int'.我应该怎么做才能解决这个问题？
回答by occulus
There's a big hint in the error message!
错误信息中有一个很大的提示！
In C and Objective C, an intis a primitive data type. You've written int *, which means "a pointer to an int", whereas it looks like you just wanted an int.
在 C 和 Objective C 中， anint是一种原始数据类型。你已经写了int *，这意味着“一个指向 int 的指针”，而看起来你只是想要一个 int。
So change your property to this:
因此，将您的属性更改为：
@property (nonatomic, assign) int myInt;
For more info, google "C pointers" and you'll find information like this: http://pw1.netcom.com/~tjensen/ptr/pointers.htm
欲了解更多信息，谷歌“C指针”，你会发现这样的信息：http: //pw1.netcom.com/~tjensen/ptr/pointers.htm
回答by Gajendra K Chauhan
Yes, simply remove asterisk (*) from declaration.
是的，只需*从声明中删除星号 ( )。
for example.declare BOOL isCheckedinstead of BOOL * isChecked.
例如.declare BOOL isChecked而不是BOOL * isChecked。
回答by Rob
Another way to resolve this is to simply not declare a pointer (drop the asterisk):
解决此问题的另一种方法是简单地不声明指针（去掉星号）：
@interface ViewController : UIViewController {
NSUInteger myObjcInt; // unsigned ( >= 0 ) NSObject int, yo
}
回答by Riwels
int *MyIntis a pointer to int, not an int.
As others told you, just remove the *and you will have a regular int.
int *MyInt是一个指向 int 的指针，而不是一个 int。
正如其他人告诉您的那样，只需删除*，您就会有一个常规的 int。
