C++ 打印出偶数
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Print out even number
提问by Patrick Wills
I just want to ask your help here. I am new beginner in c++ programming. How to print out the even number in range 100 - 200. I tried write some code and it didn't work out. Here is my code. I hope, someone here can help me. Will appreciate that so much. Thanks.
我只是想在这里请求您的帮助。我是 C++ 编程的新手。如何打印出 100 - 200 范围内的偶数。我尝试编写一些代码，但没有成功。这是我的代码。我希望这里有人可以帮助我。会非常感激。谢谢。
include <stdio.h>
void main()
{
int i;
for (i= 100; i<= 200; i += 2){
print i;
}
}
回答by Rivasa
Well, pretty simple:
嗯，很简单：
#include <iostream> // This is the C++ I/O header, has basic functions like output an input.
int main(){ // the main function is generally an int, not a void.
for(int i = 100; i <= 200; i+=2){ // for loop to advance by 2.
std::cout << i << std::endl; // print out the number and go to next line, std:: is a prefix used for functions in the std namespace.
} // End for loop
return 0; // Return int function
} // Close the int function, end of program
you were using C libraries, not C++ ones, as well as no function that is called printin C++, nor C. Also there is no void main function, use int main()instead. finally, you need to have std::in front of coutand endlas these lie in the stdnamespace.
您使用的是 C 库，而不是 C++ 库，并且没有print在 C++ 中调用的函数，也没有C. 也没有 void main 函数，请int main()改用。最后，你需要有std::前面cout，并endl为这些谎言的std命名空间。
回答by Dilletante
Your code looks good....Only the printing part needs to be changed
你的代码看起来不错....只需要改变打印部分
#include <stdio.h>
int main()
{
for (int i= 100; i<= 200; i += 2){
printf("%d",i);
}
return 0;
}
回答by Nandkumar Tekale
Use the following code:
使用以下代码：
#include <iostream>
int main()
{
int i;
for (i= 100; i<= 200; i += 2){
std::cout << i << std::endl;
}
return 0;
}
回答by The Fappening
This might help!
这可能会有所帮助！
#include <iostream>
using namespace std;
int main()
{
for (int count = 100; count <= 200; count += 2)
{
cout << count << ", ";
}
cout << endl;
return 0;
}
