Python Flask 可以有可选的 URL 参数吗？
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Can Flask have optional URL parameters?
提问by Noor
Is it possible to directly declare a flask URL optional parameter?
是否可以直接声明flask URL可选参数？
Currently I'm proceeding the following way:
目前我正在按以下方式进行：
@user.route('/<userId>')
@user.route('/<userId>/<username>')
def show(userId, username=None):
pass
How can I directly say that usernameis optional?
我怎么能直接说这username是可选的？
采纳答案by Audrius Ka?ukauskas
Another way is to write
另一种方式是写
@user.route('/<user_id>', defaults={'username': None})
@user.route('/<user_id>/<username>')
def show(user_id, username):
pass
But I guess that you want to write a single route and mark usernameas optional? If that's the case, I don't think it's possible.
但我猜你想写一个单一的路线并标记username为可选？如果是这样，我认为这是不可能的。
回答by mogul
Almost the same as Audrius cooked up some months ago, but you might find it a bit more readable with the defaults in the function head - the way you are used to with python:
与几个月前编写的 Audrius 几乎相同，但您可能会发现使用函数头中的默认值更具可读性 - 您习惯使用 python 的方式：
@app.route('/<user_id>')
@app.route('/<user_id>/<username>')
def show(user_id, username='Anonymous'):
return user_id + ':' + username
回答by Sergey Bargamon
Since Flask 0.10 you can`t add multiple routes to one endpoint. But you can add fake endpoint
从 Flask 0.10 开始，您无法向一个端点添加多个路由。但是你可以添加假端点
@user.route('/<userId>')
def show(userId):
return show_with_username(userId)
@user.route('/<userId>/<username>')
def show_with_username(userId,username=None):
pass
回答by lov3catch
You can write as you show in example, but than you get build-error.
您可以按照示例中所示进行编写，但会遇到构建错误。
For fix this:
为了解决这个问题：
- print app.url_map () in you root .py
- you see something like:
- 在你的 root .py 中打印 app.url_map()
- 你会看到类似的东西：
<Rule '/<userId>/<username>' (HEAD, POST, OPTIONS, GET) -> user.show_0>
<Rule '/<userId>/<username>' (HEAD, POST, OPTIONS, GET) -> user.show_0>
and
和
<Rule '/<userId>' (HEAD, POST, OPTIONS, GET) -> .show_1>
<Rule '/<userId>' (HEAD, POST, OPTIONS, GET) -> .show_1>
- than in template you can
{{ url_for('.show_0', args) }}and{{ url_for('.show_1', args) }}
- 比在模板中你可以
{{ url_for('.show_0', args) }}和{{ url_for('.show_1', args) }}
回答by skornos
If you are using Flask-Restful like me, it is also possible this way:
如果你像我一样使用 Flask-Restful，也可以这样：
api.add_resource(UserAPI, '/<userId>', '/<userId>/<username>', endpoint = 'user')
a then in your Resource class:
然后在您的 Resource 类中：
class UserAPI(Resource):
def get(self, userId, username=None):
pass
回答by iwasborntobleed
@user.route('/<userId>/') # NEED '/' AFTER LINK
@user.route('/<userId>/<username>')
def show(userId, username=None):
pass
https://flask.palletsprojects.com/en/1.1.x/quickstart/#unique-urls-redirection-behavior
https://flask.palletsprojects.com/en/1.1.x/quickstart/#unique-urls-redirection-behavior
回答by Sona
@app.route('/', defaults={'path': ''})
@app.route('/< path:path >')
def catch_all(path):
return 'You want path: %s' % path
回答by aman kumar
@user.route('/<user_id>', defaults={'username': default_value})
@user.route('/<user_id>/<username>')
def show(user_id, username):
#
pass
回答by Def Putra
I think you can use Blueprint and that's will make ur code look better and neatly.
我认为您可以使用 Blueprint，这将使您的代码看起来更好更整洁。
example:
例子：
from flask import Blueprint
bp = Blueprint(__name__, "example")
@bp.route("/example", methods=["POST"])
def example(self):
print("example")
回答by sudouser2010
I know this post is really old but I worked on a package that does this called flask_optional_routes. The code is located at: https://github.com/sudouser2010/flask_optional_routes.
我知道这篇文章很老了，但我开发了一个名为 flask_optional_routes 的包。代码位于：https: //github.com/sudouuser2010/flask_optional_routes。
from flask import Flask
from flask_optional_routes import OptionalRoutes
app = Flask(__name__)
optional = OptionalRoutes(app)
@optional.routes('/<user_id>/<user_name>?/')
def foobar(user_id, user_name=None):
return 'it worked!'
if __name__ == "__main__":
app.run(host='0.0.0.0', port=5000)
