python 使用 paramiko 检查远程主机上是否存在路径
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Check whether a path exists on a remote host using paramiko
提问by Sridhar Ratnakumar
Paramiko's SFTPClientapparently does not have an existsmethod. This is my current implementation:
Paramiko的SFTPClient显然没有exists方法。这是我目前的实现：
def rexists(sftp, path):
"""os.path.exists for paramiko's SCP object
"""
try:
sftp.stat(path)
except IOError, e:
if 'No such file' in str(e):
return False
raise
else:
return True
Is there a better way to do this? Checking for substring in Exception messages is pretty ugly and can be unreliable.
有一个更好的方法吗？检查异常消息中的子字符串非常难看，而且可能不可靠。
回答by Matt Good
See the errnomodulefor constants defining all those error codes. Also, it's a bit clearer to use the errnoattribute of the exception than the expansion of the __init__args, so I'd do this:
有关定义所有这些错误代码的常量，请参阅errno模块。此外，使用errno异常的属性比扩展__init__args更清晰一些，所以我会这样做：
except IOError, e: # or "as" if you're using Python 3.0
if e.errno == errno.ENOENT:
...
回答by JimB
There is no "exists" method defined for SFTP (not just paramiko), so your method is fine.
没有为 SFTP（不仅仅是 paramiko）定义“存在”方法，所以你的方法很好。
I think checking the errno is a little cleaner:
我认为检查 errno 更简洁：
def rexists(sftp, path):
"""os.path.exists for paramiko's SCP object
"""
try:
sftp.stat(path)
except IOError, e:
if e[0] == 2:
return False
raise
else:
return True
回答by jslay
Paramiko literally raises FileNotFoundError
Paramiko 字面上提出 FileNotFoundError
def sftp_exists(sftp, path):
try:
sftp.stat(path)
return True
except FileNotFoundError:
return False
