PHP - 从对象数组中按对象属性查找条目

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时间:2020-08-25 14:13:20  来源:igfitidea点击:

PHP - find entry by object property from an array of objects

phparraysobject

提问by Alex

The array looks like:

该数组看起来像:

[0] => stdClass Object
        (
            [ID] => 420
            [name] => Mary
         )

[1] => stdClass Object
        (
            [ID] => 10957
            [name] => Blah
         )
...

And I have a integer variable called $v.

我有一个名为$v.

How could I select an array entry that has a object where the IDproperty has the $vvalue ?

我怎样才能选择一个数组条目,该条目具有ID属性具有$v值的对象?

回答by Phil

You either iterate the array, searching for the particular record (ok in a one time only search) or build a hashmap using another associative array.

您可以迭代数组,搜索特定记录(可以只搜索一次)或使用另一个关联数组构建哈希图。

For the former, something like this

对于前者,像这样

$item = null;
foreach($array as $struct) {
    if ($v == $struct->ID) {
        $item = $struct;
        break;
    }
}

See this question and subsequent answers for more information on the latter - Reference PHP array by multiple indexes

有关后者的更多信息,请参阅此问题和随后的答案 -按多个索引引用 PHP 数组

回答by Daniel Hardt

YurkamTimis right. It needs only a modification:

YurkamTim是对的。它只需要修改:

After function($) you need a pointer to the external variable by "use(&$searchedValue)" and then you can access the external variable. Also you can modify it.

在 function($) 之后,您需要通过“use(&$searchedValue)”指向外部变量,然后才能访问外部变量。你也可以修改它。

$neededObject = array_filter(
    $arrayOfObjects,
    function ($e) use (&$searchedValue) {
        return $e->id == $searchedValue;
    }
);

回答by Tim

$arr = [
  [
    'ID' => 1
  ]
];

echo array_search(1, array_column($arr, 'ID')); // prints 0 (!== false)

回答by YurkaTim

I've found more elegant solution here. Adapted to the question it may look like:

我在这里找到了更优雅的解决方案。适应这个问题,它可能看起来像:

$neededObject = array_filter(
    $arrayOfObjects,
    function ($e) use ($searchedValue) {
        return $e->id == $searchedValue;
    }
);

回答by Museful

Using array_columnto re-index will save time if you need to find multiple times:

如果您需要多次查找,使用array_column重新索引将节省时间:

$lookup = array_column($arr, NULL, 'id');   // re-index by 'id'

Then you can simply $lookup[$id]at will.

然后你就可以随意$lookup[$id]了。

回答by Pablo S G Pacheco

class ArrayUtils
{
    public static function objArraySearch($array, $index, $value)
    {
        foreach($array as $arrayInf) {
            if($arrayInf->{$index} == $value) {
                return $arrayInf;
            }
        }
        return null;
    }
}

Using it the way you wanted would be something like:

以您想要的方式使用它是这样的:

ArrayUtils::objArraySearch($array,'ID',$v);

回答by Kamil Kie?czewski

Try

尝试

$entry = current(array_filter($array, function($e) use($v){ return $e->ID==$v; }));

working example here

这里的工作示例

回答by Jose Carlos Ramos Carmenates

Fixing a small mistake of the @YurkaTim, your solution work for me but adding use:

修复@YurkaTim 的一个小错误,您的解决方案对我有用,但添加use

To use $searchedValue, inside of the function, one solution can be use ($searchedValue)after function parameters function ($e) HERE.

要使用$searchedValue,在函数内部,一种解决方案可以是use ($searchedValue)在函数参数之后function ($e) HERE

the array_filterfunction only return on $neededObjectthe if the condition on return is true

array_filter函数仅$neededObject在返回条件为true

If $searchedValueis a string or integer:

如果$searchedValue是字符串或整数:

$searchedValue = 123456; // Value to search.
$neededObject = array_filter(
    $arrayOfObjects,
    function ($e) use ($searchedValue) {
        return $e->id == $searchedValue;
    }
);
var_dump($neededObject); // To see the output

If $searchedValueis array where we need check with a list:

如果$searchedValue是我们需要检查列表的数组:

$searchedValue = array( 1, 5 ); // Value to search.
$neededObject  = array_filter(
    $arrayOfObjects,
    function ( $e ) use ( $searchedValue ) {
        return in_array( $e->term_id, $searchedValue );
    }
);
var_dump($neededObject); // To see the output

回答by yuvilio

I sometimes like using the array_reduce()function to carry out the search. It's similar to array_filter() but does not affect the searched array, allowing you to carry out multiplesearches on the same array of objects.

我有时喜欢使用array_reduce()函数来执行搜索。它类似于 array_filter() 但不影响搜索到的数组,允许您对同一对象数组执行多次搜索。

$haystack = array($obj1, $obj2, ...); //some array of objects
$needle = 'looking for me?'; //the value of the object's property we want to find

//carry out the search
$search_results_array = array_reduce(
  $haystack,

  function($result_array, $current_item) use ($needle){
      //Found the an object that meets criteria? Add it to the the result array 
      if ($current_item->someProperty == $needle){
          $result_array[] = $current_item;
      }
      return $result_array;
  },
  array() //initially the array is empty (i.e.: item not found)
);

//report whether objects found
if (count($search_results_array) > 0){
  echo "found object(s): ";
  print_r($search_results_array[0]); //sample object found
} else {
  echo "did not find object(s): ";
}

回答by Mart-Jan

I did this with some sort of Java keymap. If you do that, you do not need to loop over your objects array every time.

我用某种 Java 键盘映射来做到这一点。如果这样做,则不需要每次都遍历对象数组。

<?php

//This is your array with objects
$object1 = (object) array('id'=>123,'name'=>'Henk','age'=>65);
$object2 = (object) array('id'=>273,'name'=>'Koos','age'=>25);
$object3 = (object) array('id'=>685,'name'=>'Bram','age'=>75);
$firstArray = Array($object1,$object2);
var_dump($firstArray);

//create a new array
$secondArray = Array();
//loop over all objects
foreach($firstArray as $value){
    //fill second        key          value
    $secondArray[$value->id] = $value->name;
}

var_dump($secondArray);

echo $secondArray['123'];

output:

输出:

array (size=2)
  0 => 
    object(stdClass)[1]
      public 'id' => int 123
      public 'name' => string 'Henk' (length=4)
      public 'age' => int 65
  1 => 
    object(stdClass)[2]
      public 'id' => int 273
      public 'name' => string 'Koos' (length=4)
      public 'age' => int 25
array (size=2)
  123 => string 'Henk' (length=4)
  273 => string 'Koos' (length=4)
Henk