在 Laravel json 响应中使用访问器和修改器
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Using accessors and mutators in Laravel json responses
提问by tiffanyhwang
So I'm making an API that produces a json response instead of doing View::make('foo', compact('bar')).
所以我正在制作一个生成 json 响应的 API，而不是做View::make('foo', compact('bar')).
With blade templating
带刀片模板
My controller simply returns the Eloquent model for Users:
我的控制器只是返回 Eloquent 模型Users：
public function index()
{
return User::all();
}
protected function getFooAttribute()
{
return 'bar';
}
And my view will be able to use it, along with the fooattribute (which isn't a field in the user's table).
我的视图将能够使用它以及foo属性（它不是用户表中的字段）。
@foreach($users as $user)
<p>{{$user->name}} {{$user->foo}}</p>
@endforeach
With Angular JS + json response
使用 Angular JS + json 响应
However, now that I'm not using blade but rather grabbing the jsonand displaying it with Angular JS I'm not able to do this:
但是，现在我没有使用刀片，而是json使用 Angular JS抓取并显示它，我无法做到这一点：
<p ng-repeat="user in users">{{user.name}} {{user.foo}}</p>
Is there a way to cleanly pack the json response such that I have:
有没有办法干净地打包 json 响应，以便我有：
[{"name": "John", "foo": "bar"}, ...]
Warning: I've never built an API before and I've only started programming/web dev last December. This is my attempt:
警告：我以前从未构建过 API，去年 12 月才开始编程/网络开发。这是我的尝试：
public function index()
{
$response = User::all();
foreach($response as $r)
{
$r->foo = $r->foo;
}
return $response;
}
回答by SamV
Yeah there is, example:
是的，例如：
return Response::json([User:all()], 200);
Usually you want more than that though..
但通常你想要的不止这些..
return Response::json([
'error' => false,
'data' => User:all()
], 200);
200is the HTTP Status Code.
200是 HTTP 状态代码。
To include the attributes you need to specify these attributes to automatically append onto the response in your model.
要包含属性，您需要指定这些属性以自动附加到模型的响应中。
protected $appends = array('foo');
public function getFooAttribute()
{
return 'bar';
}
