在单元测试中处理 Laravel HttpException
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Handling Laravel HttpException in Unit Testing
提问by Sean
One of my test functions for unit testing in Laravel keeps erroring out. I'm trying to assert that requesting a specific page without certain conditions being met triggers a 403 FORBIDDEN error.
我在 Laravel 中进行单元测试的一个测试函数不断出错。我试图断言在不满足某些条件的情况下请求特定页面会触发 403 FORBIDDEN 错误。
My test case function is this:
我的测试用例函数是这样的：
public function testNoAjaxCall() {
$this->call('POST', 'xyz', array());
$this->assertResponseStatus(403);
}
In the controller action this is routed to, I have this:
在路由到的控制器操作中，我有这个：
if(!Input::has('ajax') || Input::get('ajax') != 1) {
// Drop all 'non-ajax' requests.
App::abort(403, 'Normal POST requests to this page are forbidden. Please explicitly tell me you\'re using AJAX by passing ajax = 1.');
}
Running phpunit returns with the following:
运行 phpunit 返回以下内容：
1) RaceTest::testNoAjaxCall
Symfony\Component\HttpKernel\Exception\HttpException: Normal POST requests to this page are forbidden. Please explicitly tell me you're using AJAX by passing ajax = 1.
[path\to\laravel]\vendor\laravel\framework\src\Illuminate\Foundation\Application.php:875
[redacted stack trace]
[path\to\laravel]\vendor\symfony\http-kernel\Symfony\Component\HttpKernel\Client.php:81
[path\to\laravel]\vendor\symfony\browser-kit\Symfony\Component\BrowserKit\Client.php:325
[path\to\laravel]\vendor\laravel\framework\src\Illuminate\Foundation\Testing\TestCase.php:74
[path\to\laravel]\app\tests[testFileName].php:176
FAILURES!
Tests: 6, Assertions: 17, Errors: 1.
1) RaceTest::testNoAjaxCall
Symfony\Component\HttpKernel\Exception\HttpException: 禁止对该页面的正常 POST 请求。请通过传递 ajax = 1 明确告诉我您正在使用 AJAX。
[path\to\laravel]\vendor\laravel\framework\src\Illuminate\Foundation\Application.php:875
[编辑的堆栈跟踪]
[path\to\laravel]\vendor\symfony\http-kernel\Symfony\Component\HttpKernel\Client.php:81
[path\to\laravel]\vendor\symfony\browser-kit\Symfony\Component\BrowserKit\Client.php:325
[path\to\laravel]\vendor\laravel\framework\src\Illuminate\Foundation\Testing\TestCase.php:74
[path\to\laravel]\app\tests[testFileName].php:176
失败！
测试：6，断言：17，错误：1。
Of course the stack trace points back to $this->call(..);and App::abort(..)
当然，堆栈跟踪指向$this->call(..);和App::abort(..)
I have a HttpException error handler in my app/start/global.phpfile, which works when triggering it outside of unit testing (e.g. making a POSTrequest directly to the tested URL), but unit testing doesn't seem to correctly catch the exception or even reach the assert call.
我的文件中有一个 HttpException 错误处理程序，app/start/global.php它在单元测试之外触发它时起作用（例如，POST直接向测试的 URL发出请求），但单元测试似乎没有正确捕获异常，甚至没有到达断言调用。
What am I missing?
我错过了什么？
回答by crynobone
http://phpunit.de/manual/3.7/en/appendixes.annotations.html#appendixes.annotations.expectedExceptionshould already explain it.
http://phpunit.de/manual/3.7/en/appendixes.annotations.html#appendixes.annotations.expectedException应该已经解释过了。
/**
* @expectedException \Symfony\Component\HttpKernel\Exception\HttpException
* @expectedExceptionMessage Normal POST requests to this page are forbidden. Please explicitly tell me you\'re using AJAX by passing ajax = 1.
*/
public function testNoAjaxCall() {
$this->call('POST', 'xyz', array());
}
回答by Matt Votsikas
As of now, the best way I have found to assert HttpException status codes can be found in sirbarrence's work around at https://github.com/laravel/framework/issues/3979
到目前为止，我发现断言 HttpException 状态代码的最佳方法可以在 Sirbarrence 的工作中找到，网址为https://github.com/laravel/framework/issues/3979
TestCase.php:
测试用例.php：
public function assertHTTPExceptionStatus($expectedStatusCode, Closure $codeThatShouldThrow)
{
try
{
$codeThatShouldThrow($this);
$this->assertFalse(true, "An HttpException should have been thrown by the provided Closure.");
}
catch (\Symfony\Component\HttpKernel\Exception\HttpException $e)
{
// assertResponseStatus() won't work because the response object is null
$this->assertEquals(
$expectedStatusCode,
$e->getStatusCode(),
sprintf("Expected an HTTP status of %d but got %d.", $expectedStatusCode, $e->getStatusCode())
);
}
}
Usage:
用法：
public function testGetFailsWith403()
{
$this->assertHTTPExceptionStatus(403, function ($_this)
{
$_this->call('GET', '/thing-that-should-fail');
});
}
