Linux 从内核向用户空间发送信号
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Sending signal from kernel to user space
提问by mohwastz
How to get signal from kernel space to user space?
如何从内核空间获取信号到用户空间?
回答by gby
Use the kernel API function kill_proc_info(int sig, struct siginfo *info, pid_t pid)
使用内核API函数kill_proc_info(int sig, struct siginfo *info, pid_t pid)
NOTEThis is actually a bad answer. The functions does send a signal to user space but the right way to do this, as the asker intended is to use the fasync character device method as documented here: http://www.xml.com/ldd/chapter/book/ch05.html#t4
注意这实际上是一个糟糕的答案。这些函数确实向用户空间发送信号,但正确的方法是这样做,因为提问者打算使用此处记录的 fasync 字符设备方法:http://www.xml.com/ldd/chapter/book/ch05 .html#t4
回答by liv2hak
There is something called a NetLink interface which provides a set of API's for communication between a kernel process and a user process.It is similar to the socket interface and the communication is asynchronous and hence is preferred to IOCTL.
有一种叫做 NetLink 接口的东西,它为内核进程和用户进程之间的通信提供了一组 API。它类似于套接字接口,通信是异步的,因此优先于 IOCTL。
Overview here: http://www.linuxjournal.com/article/7356
回答by Raulp
To get the signal from kernel to user space use the following code in your user space and kernel space code as below :
要从内核获取信号到用户空间,请在您的用户空间和内核空间代码中使用以下代码,如下所示:
user space application :
用户空间应用:
signal(SIGIO, &signal_handler_func);
fcntl(fd, F_SETOWN, getpid());
oflags = fcntl(fd, F_GETFL);
fcntl(fd, F_SETFL, oflags | FASYNC);
define signal_handler_funcfunction :
定义signal_handler_func函数:
void signal_handler_func (int sig)
{
//handle the action corresponding to the signal here
}
kernel Space Module :
内核空间模块:
int ret = 0;
struct siginfo info;
memset(&info, 0, sizeof(struct siginfo));
info.si_signo = SIG_TEST;
info.si_code = SI_QUEUE;
info.si_int = 1234;
send_sig_info(SIG_TEST, &info, t);//send signal to user land
t is the PID of the user application.
t 是用户应用程序的 PID。