C++ 获取 OpenCV 图像类型的枚举名称（例如 CV_32FC1）？
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Getting enum names (e.g. CV_32FC1) of OpenCV image types?
提问by solvingPuzzles
In the C++ interface to OpenCV, it seems easy enough to check the type of an image. If you have an image cv::Mat img = cv::imread("someImage.xyz"), you just do int theType = img.type().
在 OpenCV 的 C++ 接口中，检查图像的类型似乎很容易。如果你有一个图像cv::Mat img = cv::imread("someImage.xyz")，你就做int theType = img.type()。
However, as you would expect, calling img.type()just gives an integer, an not an enum name (e.g. CV_32FC1).
然而，正如您所期望的，调用img.type()只给出一个整数，而不是一个枚举名称（例如CV_32FC1）。
Is there an easy way to print out the enum name (e.g. CV_32FC1) if I know the integer value of the OpenCV enum?
CV_32FC1如果我知道 OpenCV 枚举的整数值，是否有一种简单的方法可以打印出枚举名称（例如）？
回答by Sassa
To my knowledge, such a function doesn't exist in OpenCV.
据我所知，OpenCV 中不存在这样的函数。
I think you would be better off writing your own function to get those. A lot of switch cases but I guess it does the job. The enumeration can be found here.
我认为你最好编写自己的函数来获得这些。很多开关盒，但我想它可以完成工作。枚举可以在这里找到。
EDIT:
编辑：
This is something you could use to extract the types. I am guessing there could be a more efficient method, but I can't wrap my head around it right now.
这是您可以用来提取类型的东西。我猜可能有更有效的方法，但我现在无法解决它。
std::string getImageType(int number)
{
// find type
int imgTypeInt = number%8;
std::string imgTypeString;
switch (imgTypeInt)
{
case 0:
imgTypeString = "8U";
break;
case 1:
imgTypeString = "8S";
break;
case 2:
imgTypeString = "16U";
break;
case 3:
imgTypeString = "16S";
break;
case 4:
imgTypeString = "32S";
break;
case 5:
imgTypeString = "32F";
break;
case 6:
imgTypeString = "64F";
break;
default:
break;
}
// find channel
int channel = (number/8) + 1;
std::stringstream type;
type<<"CV_"<<imgTypeString<<"C"<<channel;
return type.str();
}
回答by solvingPuzzles
Following @Bob's advice, I wrote my own function to solve this problem. Here it is:
按照@Bob 的建议，我编写了自己的函数来解决这个问题。这里是：
// take number image type number (from cv::Mat.type()), get OpenCV's enum string.
string getImgType(int imgTypeInt)
{
int numImgTypes = 35; // 7 base types, with five channel options each (none or C1, ..., C4)
int enum_ints[] = {CV_8U, CV_8UC1, CV_8UC2, CV_8UC3, CV_8UC4,
CV_8S, CV_8SC1, CV_8SC2, CV_8SC3, CV_8SC4,
CV_16U, CV_16UC1, CV_16UC2, CV_16UC3, CV_16UC4,
CV_16S, CV_16SC1, CV_16SC2, CV_16SC3, CV_16SC4,
CV_32S, CV_32SC1, CV_32SC2, CV_32SC3, CV_32SC4,
CV_32F, CV_32FC1, CV_32FC2, CV_32FC3, CV_32FC4,
CV_64F, CV_64FC1, CV_64FC2, CV_64FC3, CV_64FC4};
string enum_strings[] = {"CV_8U", "CV_8UC1", "CV_8UC2", "CV_8UC3", "CV_8UC4",
"CV_8S", "CV_8SC1", "CV_8SC2", "CV_8SC3", "CV_8SC4",
"CV_16U", "CV_16UC1", "CV_16UC2", "CV_16UC3", "CV_16UC4",
"CV_16S", "CV_16SC1", "CV_16SC2", "CV_16SC3", "CV_16SC4",
"CV_32S", "CV_32SC1", "CV_32SC2", "CV_32SC3", "CV_32SC4",
"CV_32F", "CV_32FC1", "CV_32FC2", "CV_32FC3", "CV_32FC4",
"CV_64F", "CV_64FC1", "CV_64FC2", "CV_64FC3", "CV_64FC4"};
for(int i=0; i<numImgTypes; i++)
{
if(imgTypeInt == enum_ints[i]) return enum_strings[i];
}
return "unknown image type";
}
Did I forget to include any OpenCV image types in my lookup table?
我是否忘记在查找表中包含任何 OpenCV 图像类型？
