php 如何打印当前的 URL 路径?

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时间:2020-08-25 08:11:43  来源:igfitidea点击:

How to print current URL path?

phpurl

提问by TheYaXxE

I want to print out the current URL path, but my code doesn't work propperly.

我想打印出当前的 URL 路径,但我的代码不能正常工作。

I use this in my file.php

我在我的 file.php 中使用它

echo "http://".$_SERVER['HTTP_HOST'].$_SERVER['SCRIPT_NAME'];

When i open the url http://sub.mydomain.com/file.phpit seems to work fine, and it prints "http://sub.mydomain.com/file.php"

当我打开 url http://sub.mydomain.com/file.php它似乎工作正常,它打印"http://sub.mydomain.com/file.php"

But if i remove the .php extension so the url will be http://sub.mydomain.com/fileinstead, it prints "http://sub.mydomain.com/sub/file.php"which is wrong.

但是,如果我删除 .php 扩展名,那么 url 将改为http://sub.mydomain.com/file,它会打印"http://sub.mydomain.com/sub/file.php"哪个是错误的。

It prints the subdomain twice, and I don't know why?

它打印子域两次,我不知道为什么?

In my .htaccess file, I have a rewrite that makes it possible to removes .php extensions.

在我的 .htaccess 文件中,我进行了重写,可以删除 .php 扩展名。

Anyone who can/want to help me please? :)

有人可以/想要帮助我吗?:)

回答by K-Gun

You need $_SERVER['REQUEST_URI']instead of $_SERVER['SCRIPT_NAME'], cos $_SERVER['SCRIPT_NAME']will always give you the file which is working at the moment.

您需要$_SERVER['REQUEST_URI']而不是$_SERVER['SCRIPT_NAME'], cos$_SERVER['SCRIPT_NAME']将始终为您提供当前正在运行的文件。

From manual:

从手册:

SCRIPT_NAME: Contains the current script's path. This is useful for pages which need to point to themselves. The __FILE__constant contains the full path and filename of the current (i.e. included) file. .

SCRIPT_NAME:包含当前脚本的路径。这对于需要指向自身的页面很有用。该__FILE__常量包含当前(即包含的)文件的完整路径和文件名。.

I suppose this helps you getting current URL fully.

我想这可以帮助您完全获取当前 URL。

echo 'http://'. $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI'];

Notice: DO NOT RELY ON CLIENT'S HTTP_HOST, USE SERVER_NAMEINSTEAD! SEE: What is the difference between HTTP_HOST and SERVER_NAME in PHP?

注意:不要依赖客户HTTP_HOST,而是使用SERVER_NAME!参见:PHP 中的 HTTP_HOST 和 SERVER_NAME 有什么区别?

Security Warning

安全警告

You need to filter (sanitize) $_SERVER['REQUEST_URI']if you use it in anywhere (to print or store in database), cos it's not safe.

$_SERVER['REQUEST_URI']如果你在任何地方使用它(打印或存储在数据库中),你需要过滤(消毒),因为它不安全。

// ie: this could be harmfull
/user?id=123%00%27<script...

Hence, always filter user inputs before using them. At least use htmlspecialchars, htmlentities, strip_tagsetc..

因此,在使用之前总是过滤用户输入。至少使用htmlspecialcharshtmlentitiesstrip_tags等。

Or something like this;

或类似的东西;

function get_current_url($strip = true) {
    static $filter, $scheme, $host, $port; 
    if ($filter == null) {
        $filter = function($input) use($strip) {
            $input = trim($input);
            if ($input == '/') {
                return $input;
            }

            // add more chars if needed
            $input = str_ireplace(["
$main_folder = str_replace('\','/',dirname(__FILE__) );
$document_root = str_replace('\','/',$_SERVER['DOCUMENT_ROOT'] );
$main_folder = str_replace( $document_root, '', $main_folder);
if( $main_folder ) {
    $current_url = $_SERVER['REQUEST_SCHEME'].'://'.$_SERVER['SERVER_NAME']. '/' . ltrim( $main_folder, '/' ) . '/';
} else {
    $current_url = $_SERVER['REQUEST_SCHEME'].'://'.rtrim( $_SERVER['SERVER_NAME'], '/'). '/';
}
", '%00', "\x0a", '%0a', "\x1a", '%1a'], '', rawurldecode($input)); // remove markup stuff if ($strip) { $input = strip_tags($input); } // or any encoding you use instead of utf-8 $input = htmlspecialchars($input, ENT_QUOTES, 'utf-8'); return $input; }; $scheme = isset($_SERVER['REQUEST_SCHEME']) ? $_SERVER['REQUEST_SCHEME'] : ('http'. (($_SERVER['SERVER_PORT'] == '443') ? 's' : '')); $host = $_SERVER['SERVER_NAME']; $port = ($_SERVER['SERVER_PORT'] != '80' && $scheme != 'https') ? (':'. $_SERVER['SERVER_PORT']) : ''; } } return sprintf('%s://%s%s%s', $scheme, $host, $port, $filter($_SERVER['REQUEST_URI'])); }

回答by Sinan Tekmil

##代码##