C++ 将 int 附加到 char*
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Append an int to char*
提问by user37875
How would you append an integer to a char*in c++?
char*在 C++ 中，如何将整数附加到 a ？
回答by Jeremy Ruten
First convert the int to a char*using sprintf():
首先将 int 转换为char*using sprintf()：
char integer_string[32];
int integer = 1234;
sprintf(integer_string, "%d", integer);
Then to append it to your other char*, use strcat():
然后将其附加到您的其他字符 *，请使用strcat()：
char other_string[64] = "Integer: "; // make sure you allocate enough space to append the other string
strcat(other_string, integer_string); // other_string now contains "Integer: 1234"
回答by Sydius
You could also use stringstreams.
您也可以使用字符串流。
char *theString = "Some string";
int theInt = 5;
stringstream ss;
ss << theString << theInt;
The string can then be accessed using ss.str();
然后可以使用访问该字符串 ss.str();
回答by Draemon
Something like:
就像是：
width = floor(log10(num))+1;
result = malloc(strlen(str)+len));
sprintf(result, "%s%*d", str, width, num);
You could simplify len by using the maximum length for an integer on your system.
您可以通过使用系统上整数的最大长度来简化 len。
editoops - didn't see the "++". Still, it's an alternative.
编辑哎呀 - 没有看到“++”。尽管如此，它仍然是一种选择。
