ios 不处理从这里抛出的错误

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时间:2020-08-31 10:43:41  来源:igfitidea点击:

Errors thrown from here are not handled

iosjsonswiftswift3

提问by TibiaZ

I've got this problem trying to parse a JSON on my iOS app:

我在尝试在我的 iOS 应用程序上解析 JSON 时遇到了这个问题:

Relevant code:

相关代码:

let jsonData:NSDictionary = try JSONSerialization.jsonObject(with: urlData! as Data, options: JSONSerialization.ReadingOptions.mutableContainers ) as! NSDictionary

/* XCode error ^^^ Errors thrown from here are not handled */

Could anybody help me ?

有人可以帮我吗?

回答by shallowThought

A possibly thrown error in let jsonData = try JSONSerialization ...is not handled.

let jsonData = try JSONSerialization ...不处理可能抛出的错误。

You can ignore a possible error, and crash as penalty if an error occurs:

您可以忽略可能的错误,如果发生错误,则崩溃作为惩罚:

let jsonData = try! JSONSerialization ...

or return an Optional, so jsonDatais nilin error case:

或返回一个Optional,所以jsonDatanil在错误情况下:

let jsonData = try? JSONSerialization ...

or you can catch and handle the thrown error:

或者您可以捕获并处理抛出的错误:

do {
    let jsonData = try JSONSerialization ...
    //all fine with jsonData here
} catch {
    //handle error
    print(error)
}

You might want to study The Swift Language

你可能想学习The Swift Language