如果不存在则插入一条新记录，如果存在则不更新，laravel eloquent
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Insert a new record if not exist and don't update if exist, laravel eloquent
提问by Adrian Cobb
Should I use createmethod to insert a new record if doesn't exist and don't update the record if exist? Thanks.
如果create不存在，我应该使用方法插入新记录，如果存在则不更新记录吗？谢谢。
回答by Joseph Silber
Use the firstOrCreatemethod for that:
使用该firstOrCreate方法：
$user = User::firstOrCreate(['name' => 'John Doe']);
If you want to know whether the user was created or fetched, check the wasRecentlyCreatedproperty:
如果您想知道用户是创建的还是获取的，请检查wasRecentlyCreated属性：
if ($user->wasRecentlyCreated) {
// "firstOrCreate" didn't find the user in the DB, so it created it.
} else {
// "firstOrCreate" found the user in the DB and fetched it.
}
回答by Carlos Torres
In Laravel 5.2 you have the updateOrCreatemethod from Builder.php, it uses the firstOrNewmethod to verify if the given attributes exists in db and update the records with the given values or create and save the new records.
在 Laravel 5.2 中，您有updateOrCreate来自 Builder.php的方法，它使用该firstOrNew方法来验证给定的属性是否存在于 db 中，并使用给定的值更新记录或创建并保存新记录。
The weird thing is that updateOrCreatedoesn't appear in the docs:
奇怪的是updateOrCreate它没有出现在文档中：
https://laravel.com/docs/5.2/eloquent#inserting-and-updating-models
https://laravel.com/docs/5.2/eloquent#inserting-and-updating-models
/**
* Create or update a record matching the attributes, and fill it with values.
*
* @param array $attributes
* @param array $values
* @return \Illuminate\Database\Eloquent\Model
*/
public function updateOrCreate(array $attributes, array $values = [])
{
$instance = $this->firstOrNew($attributes);
$instance->fill($values)->save();
return $instance;
}
