在 C# 中动态创建数组
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原文地址: http://stackoverflow.com/questions/881133/
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Dynamically Create an Array in C#
提问by saurabh
How can I dynamically create an array in C#?
如何在 C# 中动态创建数组？
采纳答案by Bojan Resnik
You can also use the newoperator just like with other object types:
您还可以new像使用其他对象类型一样使用运算符：
int[] array = new int[5];
or, with a variable:
或者，使用变量：
int[] array = new int[someLength];
回答by Natrium
First make an arraylist. Add/remove items. And then ArrayList.ToArray()
首先制作一个数组列表。添加/删除项目。进而ArrayList.ToArray()
And there is your array!
还有你的阵列！
回答by Matthew Flaschen
object foo = Array.CreateInstance(typeof(byte), length);
回答by Gerrie Schenck
I'd like to add to Natrium's answer that generic collections also support this .ToArray() method.
我想在 Natrium 的回答中补充一点，泛型集合也支持这个 .ToArray() 方法。
List<string> stringList = new List<string>();
stringList.Add("1");
stringList.Add("2");
stringList.Add("3");
string[] stringArray = stringList.ToArray();
回答by blitzkriegz
Use generic List or ArrayList.
使用通用列表或 ArrayList。
回答by Michael Dausmann
Ok so array initialisation gets me every single time. so I took 10 minutes to do this right.
好吧，数组初始化每次都让我得到。所以我花了 10 分钟才把这件事做好。
static void Main(string[] args)
{
String[] as1 = new String[] { "Static", "with", "initializer" };
ShowArray("as1", as1);
String[] as2 = new String[5];
as2[0] = "Static";
as2[2] = "with";
as2[3] = "initial";
as2[4] = "size";
ShowArray("as2", as2);
ArrayList al3 = new ArrayList();
al3.Add("Dynamic");
al3.Add("using");
al3.Add("ArrayList");
//wow! this is harder than it should be
String[] as3 = (String[])al3.ToArray(typeof(string));
ShowArray("as3", as3);
List<string> gl4 = new List<string>();
gl4.Add("Dynamic");
gl4.Add("using");
gl4.Add("generic");
gl4.Add("list");
//ahhhhhh generic lubberlyness :)
String[] as4 = gl4.ToArray();
ShowArray("as4", as4);
}
private static void ShowArray(string msg, string[] x)
{
Console.WriteLine(msg);
for(int i=0;i<x.Length;i++)
{
Console.WriteLine("item({0})={1}",i,x[i]);
}
}
回答by sina rezaei
int[] array = { 1, 2, 3, 4, 5};
for (int i=0;i<=array.Length-1 ;i++ ) {
Console.WriteLine(array[i]);
}
