读取用户输入直到输入 0 的 Java 程序，还会进行一些计算（偶数/几率、平均值等）
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原文地址: http://stackoverflow.com/questions/48482222/
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Java program that reads user input until 0 is entered, also makes a few calculations (evens/odds, average, etc.)
提问by Sharon Nystrom
This program is meant to take user input until a zero is entered, and then print out information on the integers. It's also meant to read if the input in even/odd, calculate the sum, find the largest and smallest entered integers, tally the total integers entered, and find the average. It won't stop when the user enters 0, and it won't print the "No data entered" line if there's no input. It also isn't figuring even numbers properly.
该程序旨在接受用户输入，直到输入零，然后打印出有关整数的信息。它还意味着读取输入是否为偶数/奇数，计算总和，找到输入的最大和最小整数，计算输入的总整数，并找到平均值。当用户输入 0 时它不会停止，如果没有输入，它不会打印“未输入数据”行。它也没有正确计算偶数。
import java.util.Scanner;
public class Lab4 {
public static void main(String[] args) {
int counter = 0;
double even = 0;
double odd = 0;
double sum = 0;
int input = 0;
int large = 0;
int small = 0;
double average;
System.out.print("Enter a series of values (0 to quit): ");
Scanner in = new Scanner(System.in);
while ((input = in.nextInt()) != 0) {
small = in.nextInt();
large = in.nextInt();
if (input != 0)
sum = input + sum;
counter++;
if (input > large)
large = input;
if (input < small)
small = input;
if (input % 2 == 0)
even = even + 1;
else
odd = odd + 1;
}
if (counter > 0) {
average = sum / counter;
System.out.println("The smallest integer is: " + small);
System.out.println("The largest integer is: " + large);
System.out.println("Total number of integers entered is " + counter);
System.out.println("Total even numbers entered is " + even);
System.out.println("Total odd numbers entered is " + odd);
System.out.println("The average value is: " + average);
} else {
System.out.println("No data was entered.");
}
}
}
采纳答案by devilfart
When reading the first numbers to populate large and small we only need to do that once. And without re-reading the numbers with in.nextInt()because that will eat up the next inputs that are entered, which was probably causing the not terminating at zero error.
当读取第一个数字来填充大小时，我们只需要这样做一次。并且无需重新读取数字，in.nextInt()因为这会耗尽输入的下一个输入，这可能导致不以零错误终止。
while ((input = in.nextInt()) != 0) {
if (counter == 0)
small = large = input;
if (input != 0)
sum = input + sum;
counter++;
if (input > large)
large = input;
if (input < small)
small = input;
if (input % 2 == 0)
even = even + 1;
else
odd = odd + 1;
}
回答by Elliott Frisch
You are inputting extra numbers in the loop body for largeand small. Use ++instead of += 1, I would prefer Integer.minand Integer.max; initialize smalland largeto something very large and very small respectively. Something like,
您在循环体中为largeand输入了额外的数字small。使用++代替+= 1，我更喜欢Integer.min和Integer.max；分别初始化small和large到非常大和非常小的东西。就像是，
double even = 0, odd = 0, sum = 0;
int counter = 0, input = 0, large = Integer.MIN_VALUE, small = Integer.MAX_VALUE;
System.out.print("Enter a series of values (0 to quit): ");
Scanner in = new Scanner(System.in);
while ((input = in.nextInt()) != 0) {
small = Integer.min(small, input);
large = Integer.max(large, input);
sum += input;
counter++;
if (input % 2 == 0) {
even++;
} else {
odd++;
}
}
if (counter > 0) {
double average = sum / counter;
System.out.println("The smallest integer is: " + small);
System.out.println("The largest integer is: " + large);
System.out.println("Total number of integers entered is " + counter);
System.out.println("Total even numbers entered is " + even);
System.out.println("Total odd numbers entered is " + odd);
System.out.println("The average value is: " + average);
} else {
System.out.println("No data was entered.");
}
