将图像编码为 base64,得到一个无效的 base64 字符串(ios 使用 base64EncodedStringWithOptions)

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时间:2020-08-30 23:39:33  来源:igfitidea点击:

encode image to base64, get a invalid base64 string (ios using base64EncodedStringWithOptions)

iosimagefile-uploadbase64nativeapplication

提问by Yu-Shing Shen

Here is my code.

这是我的代码。

  UIImage *img = [UIImage imageNamed:@"white.jpeg"];
  NSData *imageData = UIImagePNGRepresentation(img);
  NSString *imageString = [imageData base64EncodedStringWithOptions:0];
  NSLog(@"%@", imageString);

And I always get invalid base64 string which include space.

而且我总是得到包含空格的无效 base64 字符串。

iVBORw0KGgoAAAANSUhEUgAAARMAAAC3CAIAAAC MS2jAAAAHGlET1QAAAACAAAAAAAAAFwAAAAoAAAAXAAAAFsAAAMC oRdmgAAAs5JREFUeAHs1tFKI1EABFH//5NNVh02uA LQhwoCZ0zj5LbTlffInl58yCAwM8JvPz8iBMIIPDGHJcAgTMEmHOGmjMIMMcdQOAMAeacoeYMAsxxBxA4Q4A5Z6g5gwBz3IGHIPD zfMQL/fVSzDnKyr 9usEvhHn/ddf5N5/yJx7SflcSoA5KV7hz0Lgn0gPW9h3zsNO81wvdr1e/3w R3PmPNf82p4mcLlcDnlu/txCbvKcDqwP s6pCcu/i8Bhzn/yMOcucD705ARe/z43eY5fbQcN5jz5lVB/k4Bfa5u7alUTYE5NWP4mAeZs7qpVTYA5NWH5mwSYs7mrVjUB5tSE5W8SYM7mrlrVBJhTE5a/SYA5m7tqVRNgTk1Y/iYB5mzuqlVNgDk1YfmbBJizuatWNQHm1ITlbxJgzuauWtUEmFMTlr9JgDmbu2pVE2BOTVj JgHmbO6qVU2AOTVh ZsEmLO5q1Y1AebUhOVvEmDO5q5a1QSYUxOWv0mAOZu7alUTYE5NWP4mAeZs7qpVTYA5NWH5mwSYs7mrVjUB5tSE5W8SYM7mrlrVBJhTE5a/SYA5m7tqVRNgTk1Y/iYB5mzuqlVNgDk1YfmbBJizuatWNQHm1ITlbxJgzuauWtUEmFMTlr9JgDmbu2pVE2BOTVj JgHmbO6qVU2AOTVh ZsEmLO5q1Y1AebUhOVvEmDO5q5a1QSYUxOWv0mAOZu7alUTYE5NWP4mAeZs7qpVTYA5NWH5mwSYs7mrVjUB5tSE5W8SYM7mrlrVBJhTE5a/SYA5m7tqVRNgTk1Y/iYB5mzuqlVNgDk1YfmbBJizuatWNQHm1ITlbxJgzuauWtUEmFMTlr9JgDmbu2pVE2BOTVj JgHmbO6qVU2AOTVh ZsEmLO5q1Y1AebUhOVvEmDO5q5a1QSYUxOWv0mAOZu7alUTYE5NWP4mAeZs7qpVTeADAAD//66TqMcAAAIISURBVO3TsQ0AAAjDMP4/GnEDmc3exSKzjgCBv8D8JxYECKxyPAGBIqCcomZDQDl gEARUE5RsyGgHD9AoAgop6jZEFCOHyBQBJRT1GwIKMcPECgCyilqNgSU4wcIFAHlFDUbAsrxAwSKgHKKmg0B5fgBAkVAOUXNhoBy/ACBIqCcomZDQDl gEARUE5RsyGgHD9AoAgop6jZEFCOHyBQBJRT1GwIKMcPECgCyilqNgSU4wcIFAHlFDUbAsrxAwSKgHKKmg0B5fgBAkVAOUXNhoBy/ACBIqCcomZDQDl gEARUE5RsyGgHD9AoAgop6jZEFCOHyBQBJRT1GwIKMcPECgCyilqNgSU4wcIFAHlFDUbAsrxAwSKgHKKmg0B5fgBAkVAOUXNhoBy/ACBIqCcomZDQDl gEARUE5RsyGgHD9AoAgop6jZEFCOHyBQBJRT1GwIKMcPECgCyilqNgSU4wcIFAHlFDUbAsrxAwSKgHKKmg0B5fgBAkVAOUXNhoBy/ACBIqCcomZDQDl gEARUE5RsyGgHD9AoAgop6jZEFCOHyBQBJRT1GwIKMcPECgCyilqNgSU4wcIFAHlFDUbAsrxAwSKgHKKmg0B5fgBAkVAOUXNhoBy/ACBIqCcomZDQDl gEARUE5RsyGgHD9AoAgop6jZEFCOHyBQBJRT1GwIKMcPECgCB/GnRcSfso/fAAAAAElFTkSuQmCC

So Confused.

如此迷茫。

When I try remove the space in base64 string, and decode it.

当我尝试删除 base64 字符串中的空格并对其进行解码时。

I can't get origin image.

我无法获得原始图像。

回答by Logan

I think you should replace the your options parameter

我认为你应该替换你的选项参数

Change:

改变:

NSString *imageString = [imageData base64EncodedStringWithOptions:0];

To:

到:

NSString *imageString = [imageData base64EncodedStringWithOptions:NSDataBase64EncodingEndLineWithLineFeed];

And just in case you'd like it:

以防万一你喜欢它:

- (NSString *)imageToNSString:(UIImage *)image
{
    NSData *data = UIImagePNGRepresentation(image);

    return [data base64EncodedStringWithOptions:NSDataBase64EncodingEndLineWithLineFeed];
}

- (UIImage *)stringToUIImage:(NSString *)string
{
    NSData *data = [[NSData alloc]initWithBase64EncodedString:string options:NSDataBase64DecodingIgnoreUnknownCharacters];

    return [UIImage imageWithData:data];
}

Remember that this is an iOS 7 api.

请记住,这是一个 iOS 7 api。

回答by Fadi Abuzant

replace +to %2Bios replace all + to " " space that make image invalid

+替换为%2Bios 将所有 + 替换为“” 使图像无效的空格

also backend must handle it too

后端也必须处理它

- (NSString *)base64String:(UIImage*)image {return [[UIImageJPEGRepresentation(image,1) base64EncodedStringWithOptions:NSDataBase64EncodingEndLineWithLineFeed] stringByReplacingOccurrencesOfString:@"+" withString:@"%2B"];}

回答by Yu-Shing Shen

Yap, I find the problem is I don't encode the url.

是的,我发现问题是我没有对 url 进行编码。

In the post data my base64 "+" character was translate to " " character.

在帖子数据中,我的 base64 "+" 字符被转换为 " " 字符。

So I get the invalid base64 string.

所以我得到了无效的 base64 字符串。

Thanks Logan.

谢谢洛根。

回答by Amr Angry

inspired from Fadi Abuzant answer here is the Swift 3 version

受 Fadi Abuzant 的启发,这里的答案是 Swift 3 版本

stringBase64 = stringBase64.replacingOccurrences(of: "+", with: "%2B")