从 iOS 中的纬度和经度获取位置名称
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Get location name from Latitude & Longitude in iOS
提问by Krunal
I want to find current location name from latitude and longitude,
我想从纬度和经度中找到当前的位置名称，
Here is my code snippet I tried but my log shows null value in all the places except in placemark, placemark.ISOcountryCodeand placemark.country
这是我尝试过的代码片段，但我的日志在除 in 之外的所有地方都显示空值placemark，placemark.ISOcountryCode并且placemark.country
I want value of placemark.localityand placemark.subLocalitybut it is showing null values.
我想要的价值placemark.locality，并placemark.subLocality却是露出空值。
- (void)viewWillAppear:(BOOL)animated
{
[super viewWillAppear:animated];
// this creates the CCLocationManager that will find your current location
locationManager = [[CLLocationManager alloc] init];
locationManager.delegate = self;
locationManager.desiredAccuracy = kCLLocationAccuracyNearestTenMeters;
[locationManager startUpdatingLocation];
}
// this delegate is called when the app successfully finds your current location
- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation
{
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
[geocoder reverseGeocodeLocation:locationManager.location
completionHandler:^(NSArray *placemarks, NSError *error) {
NSLog(@"reverseGeocodeLocation:completionHandler: Completion Handler called!");
if (error){
NSLog(@"Geocode failed with error: %@", error);
return;
}
NSLog(@"placemarks=%@",[placemarks objectAtIndex:0]);
CLPlacemark *placemark = [placemarks objectAtIndex:0];
NSLog(@"placemark.ISOcountryCode =%@",placemark.ISOcountryCode);
NSLog(@"placemark.country =%@",placemark.country);
NSLog(@"placemark.postalCode =%@",placemark.postalCode);
NSLog(@"placemark.administrativeArea =%@",placemark.administrativeArea);
NSLog(@"placemark.locality =%@",placemark.locality);
NSLog(@"placemark.subLocality =%@",placemark.subLocality);
NSLog(@"placemark.subThoroughfare =%@",placemark.subThoroughfare);
}];
}
// this delegate method is called if an error occurs in locating your current location
- (void)locationManager:(CLLocationManager *)manager didFailWithError:(NSError *)error
{
NSLog(@"locationManager:%@ didFailWithError:%@", manager, error);
}
Thanks In Advance.
提前致谢。
EDIT:
编辑：
- (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation
{
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
CLLocation *currentLocation = newLocation;
if (currentLocation != nil)
NSLog(@"longitude = %.8f\nlatitude = %.8f", currentLocation.coordinate.longitude,currentLocation.coordinate.latitude);
// stop updating location in order to save battery power
[locationManager stopUpdatingLocation];
[geocoder reverseGeocodeLocation:currentLocation completionHandler:^(NSArray *placemarks, NSError *error)
{
NSLog(@"Found placemarks: %@, error: %@", placemarks, error);
if (error == nil && [placemarks count] > 0)
{
CLPlacemark *placemark = [placemarks lastObject];
// strAdd -> take bydefault value nil
NSString *strAdd = nil;
if ([placemark.subThoroughfare length] != 0)
strAdd = placemark.subThoroughfare;
if ([placemark.thoroughfare length] != 0)
{
// strAdd -> store value of current location
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark thoroughfare]];
else
{
// strAdd -> store only this value,which is not null
strAdd = placemark.thoroughfare;
}
}
if ([placemark.postalCode length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark postalCode]];
else
strAdd = placemark.postalCode;
}
if ([placemark.locality length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark locality]];
else
strAdd = placemark.locality;
}
if ([placemark.administrativeArea length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark administrativeArea]];
else
strAdd = placemark.administrativeArea;
}
if ([placemark.country length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark country]];
else
strAdd = placemark.country;
}
}
}];
}
采纳答案by Niru Mukund Shah
I'm giving you snippet which I'm using for resolving address. I'm including comment also at neccessary place to understand the code for you. Besides that feel free to ask any question from snippet if you get fail to understand anything.
我给你我用来解析地址的片段。我也在必要的地方添加了评论，以便为您理解代码。除此之外，如果您无法理解任何内容，请随时从片段中提出任何问题。
Write following snippet in didUpdateToLocationmethod
在didUpdateToLocation方法中编写以下代码段
NSLog(@"didUpdateToLocation: %@", newLocation);
CLLocation *currentLocation = newLocation;
if (currentLocation != nil)
NSLog(@"longitude = %.8f\nlatitude = %.8f", currentLocation.coordinate.longitude,currentLocation.coordinate.latitude);
// stop updating location in order to save battery power
[locationManager stopUpdatingLocation];
// Reverse Geocoding
NSLog(@"Resolving the Address");
// “reverseGeocodeLocation” method to translate the locate data into a human-readable address.
// The reason for using "completionHandler" ----
// Instead of using delegate to provide feedback, the CLGeocoder uses “block” to deal with the response. By using block, you do not need to write a separate method. Just provide the code inline to execute after the geocoding call completes.
[geocoder reverseGeocodeLocation:currentLocation completionHandler:^(NSArray *placemarks, NSError *error)
{
NSLog(@"Found placemarks: %@, error: %@", placemarks, error);
if (error == nil && [placemarks count] > 0)
{
placemark = [placemarks lastObject];
// strAdd -> take bydefault value nil
NSString *strAdd = nil;
if ([placemark.subThoroughfare length] != 0)
strAdd = placemark.subThoroughfare;
if ([placemark.thoroughfare length] != 0)
{
// strAdd -> store value of current location
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark thoroughfare]];
else
{
// strAdd -> store only this value,which is not null
strAdd = placemark.thoroughfare;
}
}
if ([placemark.postalCode length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark postalCode]];
else
strAdd = placemark.postalCode;
}
if ([placemark.locality length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark locality]];
else
strAdd = placemark.locality;
}
if ([placemark.administrativeArea length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark administrativeArea]];
else
strAdd = placemark.administrativeArea;
}
if ([placemark.country length] != 0)
{
if ([strAdd length] != 0)
strAdd = [NSString stringWithFormat:@"%@, %@",strAdd,[placemark country]];
else
strAdd = placemark.country;
}
Where strAdd will return address using geolocation..
其中 strAdd 将使用地理定位返回地址..
Enjoy Programming !!
享受编程！！
回答by AndrewK
Method with completion block:
带有完成块的方法：
typedef void(^addressCompletion)(NSString *);
-(void)getAddressFromLocation:(CLLocation *)location complationBlock:(addressCompletion)completionBlock
{
__block CLPlacemark* placemark;
__block NSString *address = nil;
CLGeocoder* geocoder = [CLGeocoder new];
[geocoder reverseGeocodeLocation:location completionHandler:^(NSArray *placemarks, NSError *error)
{
if (error == nil && [placemarks count] > 0)
{
placemark = [placemarks lastObject];
address = [NSString stringWithFormat:@"%@, %@ %@", placemark.name, placemark.postalCode, placemark.locality];
completionBlock(address);
}
}];
}
This is how to use it:
这是如何使用它：
CLLocation* eventLocation = [[CLLocation alloc] initWithLatitude:_latitude longitude:_longitude];
[self getAddressFromLocation:eventLocation complationBlock:^(NSString * address) {
if(address) {
_address = address;
}
}];
回答by Paula Hasstenteufel
I implemented Niru's solution in Swift 3, posting here should anybody need it:
我在Swift 3 中实现了 Niru 的解决方案，如果有人需要，请在此处发布：
let geocoder = CLGeocoder()
geocoder.reverseGeocodeLocation(self.location!) { (placemarksArray, error) in
if (placemarksArray?.count)! > 0 {
let placemark = placemarksArray?.first
let number = placemark!.subThoroughfare
let bairro = placemark!.subLocality
let street = placemark!.thoroughfare
self.addressLabel.text = "\(street!), \(number!) - \(bairro!)"
}
}
回答by Deepak Srivastava
Use google api for reverse geotagging :
使用 google api 进行反向地理标记：
URL : http://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452&sensor=true_or_false
网址：http: //maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452&sensor=true_or_false
From : https://developers.google.com/maps/documentation/geocoding/
来自：https: //developers.google.com/maps/documentation/geocoding/
回答by iOS
In Swift 4.1 and Xcode 9.4.1, this is one of my solution. Here i'm using geocodeAPI to get the complete address. With this api i can get the village names also.
在 Swift 4.1 和 Xcode 9.4.1 中，这是我的解决方案之一。在这里，我使用地理编码API 来获取完整地址。有了这个api，我也可以得到村庄的名字。
I'm using reverseGeocodeLocationbut it's not getting village address details or village names, it's getting only near by city names. It's one of the finest solution....
我正在使用reverseGeocodeLocation但它没有获得村庄地址详细信息或村庄名称，它只能通过城市名称获得。这是最好的解决方案之一......
func getAddressForLatLng(latitude: String, longitude: String) { // Call this function
let url = NSURL(string: "https://maps.googleapis.com/maps/api/geocode/json?latlng=\(latitude),\(longitude)")//Here pass your latitude, longitude
print(url!)
let data = NSData(contentsOf: url! as URL)
if data != nil {
let json = try! JSONSerialization.jsonObject(with: data! as Data, options: JSONSerialization.ReadingOptions.allowFragments) as! NSDictionary
print(json)
let status = json["status"] as! String
if status == "OK" {
if let result = json["results"] as? NSArray {
if result.count > 0 {
if let addresss:NSDictionary = result[0] as? NSDictionary {
if let address = addresss["address_components"] as? NSArray {
var newaddress = ""
var number = ""
var street = ""
var city = ""
var state = ""
var zip = ""
var country = ""
if(address.count > 1) {
number = (address.object(at: 0) as! NSDictionary)["short_name"] as! String
}
if(address.count > 2) {
street = (address.object(at: 1) as! NSDictionary)["short_name"] as! String
}
if(address.count > 3) {
city = (address.object(at: 2) as! NSDictionary)["short_name"] as! String
}
if(address.count > 4) {
state = (address.object(at: 4) as! NSDictionary)["short_name"] as! String
}
if(address.count > 6) {
zip = (address.object(at: 6) as! NSDictionary)["short_name"] as! String
}
newaddress = "\(number) \(street), \(city), \(state) \(zip)"
print(newaddress)
// OR
//This is second type to fetch pincode, country, state like this type of data
for i in 0..<address.count {
print(((address.object(at: i) as! NSDictionary)["types"] as! Array)[0])
if ((address.object(at: i) as! NSDictionary)["types"] as! Array)[0] == "postal_code" {
zip = (address.object(at: i) as! NSDictionary)["short_name"] as! String
}
if ((address.object(at: i) as! NSDictionary)["types"] as! Array)[0] == "country" {
country = (address.object(at: i) as! NSDictionary)["long_name"] as! String
}
if ((address.object(at: i) as! NSDictionary)["types"] as! Array)[0] == "administrative_area_level_1" {
state = (address.object(at: i) as! NSDictionary)["long_name"] as! String
}
if ((address.object(at: i) as! NSDictionary)["types"] as! Array)[0] == "administrative_area_level_2" {
district = (address.object(at: i) as! NSDictionary)["long_name"] as! String
}
}
}
}
}
}
}
}
}
Call this function like this
像这样调用这个函数
self.getAddressForLatLng(latitude: "\(self.lat!)", longitude: "\(self.lng!)")
回答by Gurjinder Singh
Swift 5
斯威夫特 5
import CoreLocation
func printAddress() {
if let lat = Double(30.710489), lat != 0.0, let long = Double(76.852386), long != 0.0 {
// Create Location
let location = CLLocation(latitude: lat, longitude: long)
// Geocode Location
CLGeocoder().reverseGeocodeLocation(location) { (placemarks, error) in
// Process Response
self.processResponse(withPlacemarks: placemarks, error: error)
}
}
}
private func processResponse(withPlacemarks placemarks: [CLPlacemark]?, error: Error?) {
var address = ""
if let error = error {
address = "Unable to Reverse Geocode Location (\(error))"
} else {
if let placemarks = placemarks, let placemark = placemarks.first {
address = placemark.compactAddress ?? ""
} else {
address = "No address found"
}
}
print(address)
}
extension CLPlacemark {
var compactAddress: String? {
if let name = name {
var result = name
if let street = thoroughfare {
result += ", \(street)"
}
if let city = locality {
result += ", \(city)"
}
if let postalCode = postalCode {
result += ", \(postalCode)"
}
if let country = country {
result += ", \(country)"
}
return result
}
return nil
}
}
// 2nd Way
func updateLocation(lat:Double,long:Double) {
CLGeocoder().reverseGeocodeLocation(CLLocation(latitude: Double(lat), longitude: Double(long)), completionHandler: { (placemarks, error) -> Void in
if error != nil {
return
}
else {
var location = ""
let pm = placemarks![0]
if pm.addressDictionary!["FormattedAddressLines"] != nil {
location = "\n" + (pm.addressDictionary!["FormattedAddressLines"] as! NSArray).componentsJoined(by: ", ")
}else{
location = "\n" + "NO_ADDRESS_FOUND"
}
}
})
}
回答by kalpesh
Try this
尝试这个
[geocoder reverseGeocodeLocation:currentLocation completionHandler:^(NSArray *placemarks, NSError *error) {
//..NSLog(@"Found placemarks: %@, error: %@", placemarks, error);
if (error == nil && [placemarks count] > 0) {
placemark = [placemarks lastObject];
lblgetaddrees.text = [NSString stringWithFormat:@"%@,%@,%@,%@,%@,%@",
placemark.subThoroughfare, placemark.thoroughfare,
placemark.postalCode, placemark.locality,
placemark.administrativeArea,
placemark.country];
} else {
//..NSLog(@"%@", error.debugDescription);
}
} ];
回答by Deepesh Gairola
Once you have latitude, longitudevalues of a location you can use CLGeocoderhere is a tutorialwhich might help you.
一旦你有latitude，longitude位置值可以使用CLGeocoder这里是一个教程这可能会帮助你。
回答by Balu
use this API for getting the data and pass lat and long values.
使用此 API 获取数据并传递经纬度值。
回答by Ahmed Z.
If the location you are trying to get is listed in this list then there is something wrong in your code..
如果您尝试获取的位置列在此列表中，则您的代码有问题。
http://developer.apple.com/library/ios/#technotes/tn2289/_index.html#//apple_ref/doc/uid/DTS40011305
http://developer.apple.com/library/ios/#technotes/tn2289/_index.html#//apple_ref/doc/uid/DTS40011305
otherwise CLGeoCoder doesnt have addresses to other countries.
否则 CLGeoCoder 没有其他国家的地址。
I faced the same problem so i used this to get the address.. Gives a really accurate address.
我遇到了同样的问题，所以我用它来获取地址..给出了一个非常准确的地址。
http://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452&sensor=true_or_false
http://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452&sensor=true_or_false
