BASH Base64 编码脚本编码不正确
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BASH Base64 Encode script not encoding right
提问by jfreak53
I am trying to get a base64 encode to work and output to a variable in a bash script. The regular cli syntax is:
我试图让 base64 编码工作并输出到 bash 脚本中的变量。常规的 cli 语法是：
echo -ne "auth=$(echo -ne "AG15dXNlckBteWhvc3QuY29tAG15cGFzcw==
$user@$hostLW5lIAo=
$pass" | base64);
[email protected]#!/bin/bash
user=myuser
pass=mypass
host=myhost.com
auth=$(echo -ne "[51][00:33:22] vlazarenko@alluminium (~/tests) > echo -ne "user=myuser
pass=mypass
host=myhost.com
auth=$(printf "##代码##%s@%s##代码##%s" "$user" "$host" "$pass" | base64)
[email protected]##代码##mypass" | base64
AG15dXNlckBteWhvc3QuY29tAG15cGFzcw==
[52][00:33:42] vlazarenko@alluminium (~/tests) > bash base64.sh
AG15dXNlckBteWhvc3QuY29tAG15cGFzcw==
[53][00:33:46] vlazarenko@alluminium (~/tests) > dash base64.sh
LW5lIAo=
$user@$host##代码##$pass" | base64);
echo $auth
mypass" | base64
But when I try putting this into a variable in a script it outputs, but a very small encoding, so I know it's not working. My code in the script is:
但是当我尝试将它放入脚本中的变量时，它会输出一个非常小的编码，所以我知道它不起作用。我在脚本中的代码是：
##代码##I know it has something to do with the quotes, but I've tried a myriad of thing's with different quotes and singles and backslashes with no go.
我知道这与引号有关，但我尝试了无数带有不同引号、单引号和反斜杠的方法，但没有成功。
Any thoughts?
有什么想法吗？
EDIT: A bit more for the info. This should output with the user/pass/host above:
编辑：更多信息。这应该与上面的 user/pass/host 一起输出：
##代码##But in the script it outputs:
但在脚本中它输出：
##代码##回答by favoretti
Ok, I'll add this as an answer for the records's sake:
好的，为了记录，我将其添加为答案：
Problem was in having /bin/shas a default interpreter shell, which I assume, in this case was dash.
问题在于有/bin/sh一个默认的解释器 shell，我假设在这种情况下是dash.
Test script used:
使用的测试脚本：
##代码##Results:
结果：
##代码##回答by Gordon Davisson
Different versions of echobehave very differently when you give them anything other than a plain string. Some interpret command options (like -ne), while some just print them as output; some interpret escape sequences in the string (even if not given a -eoption), some don't.
echo当你给它们提供除普通字符串以外的任何东西时，不同版本的行为非常不同。一些解释命令选项（如-ne），而另一些只是将它们打印为输出；有些解释字符串中的转义序列（即使没有给出-e选项），有些则不解释。
If you want consistent behavior, use printfinstead:
如果您想要一致的行为，请printf改用：
As a bonus, since the password (and username and host) are in plain strings rather than the format string, it won't make a mess trying to interpret escape sequences in them (does your real password have a backslash in it?)
作为奖励，由于密码（以及用户名和主机）是纯字符串而不是格式字符串，因此尝试解释其中的转义序列不会造成混乱（您的真实密码中是否有反斜杠？）
