bash 如何将grep的输出传递给sed？
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How to pass output of grep to sed?
提问by batman
I have a command like this :
我有一个这样的命令：
cat error | grep -o [0-9]
which is printing only numbers like 2,30and so on. Now I wish to pass thisnumber to sed.
它只打印数字，如2，30等等。现在我希望将这个数字传递给sed.
Something like :
就像是 ：
cat error | grep -o [0-9] | sed -n '$OutPutFromGrep,$OutPutFromGrepp'
Is it possible to do so?
有可能这样做吗？
I'm new to shell scripting. Thanks in advance
我是 shell 脚本的新手。提前致谢
采纳答案by Thor
If the intention is to print the lines that grepreturns, generating a sedscript might be the way to go:
如果打算打印grep返回的行，则生成sed脚本可能是要走的路：
grep -E -o '[0-9]+' error | sed 's/$/p/' | sed -f - error
回答by themel
You are probably looking for xargs, particularly the -Ioption:
您可能正在寻找xargs，尤其是以下-I选项：
themel@eristoteles:~$ xargs -I FOO echo once FOO, twice FOO
hi
once hi, twice hi
there
once there, twice there
Your example:
你的例子：
themel@eristoteles:~$ cat error
error in line 123
error in line 234
errors in line 345 and 346
themel@eristoteles:~$ grep -o '[0-9]*' < error | xargs -I OutPutFromGrep echo sed -n 'OutPutFromGrep,OutPutFromGrepp'
sed -n 123,123p
sed -n 234,234p
sed -n 345,345p
sed -n 346,346p
For real-world use, you'll probably want to pass sedan input file and remove the echo.
对于实际使用，您可能希望传递sed输入文件并删除echo.
(Fixed your UUOC, by the way. )
（顺便说一下，修复了你的UUOC。）
回答by Ivaylo Strandjev
Yes you can pass output from grep to sed.
是的，您可以将输出从 grep 传递到 sed。
Please note that in order to match whole numbers you need to use [0-9]* not only [0-9] which would match only a single digit.
请注意，为了匹配整数，您需要使用 [0-9]* 而不仅仅是 [0-9]，后者只能匹配一位数字。
Also note you should use double quotes to get variables expanded(in the sed argument) and it seems you have a typo in the second variable name.
另请注意，您应该使用双引号来扩展变量（在 sed 参数中），而且您似乎在第二个变量名称中有拼写错误。
Hope this helps.
希望这可以帮助。
