在python中是否有不小于或不大于的操作？
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Is there an operation for not less than or not greater than in python?
提问by Peaceful
Consider a following snippet:
考虑以下片段：
a = 0
if a == 0 or a > 0:
print(a)
Essentially, I want to do something when ais not negative. If instead of this, I had wanted to do something when ais not 0, I would have simply written:
本质上，我想做一些事情a不是消极的。如果不是这样，我想要在ais not时做某事0，我会简单地写：
if a != 0 :
In the same spirit, I tried :
本着同样的精神，我尝试过：
if a !< 0 :
assuming the consistency of the Python where user starts guessing the correct implementations once he/she gets used to the language. I was surprised to see that this particular operation does not exist in Python! My question is that why such simple thing has not been implemented in Python and is there another way in which it has been implemented. Any feedback is highly appreciated. Thank you
假设 Python 的一致性，用户一旦习惯了该语言就开始猜测正确的实现。我很惊讶地看到 Python 中不存在这个特定的操作！我的问题是，为什么这么简单的事情没有在 Python 中实现，是否还有另一种实现方式。任何反馈都受到高度赞赏。谢谢
回答by Michael Zhang
Instead of a == 0 or a > 0you could just use a >= 0.
而不是a == 0 or a > 0你可以使用a >= 0.
回答by DeepSpace
I was surprised to see that this particular operation does not exist in Python!
我很惊讶地看到 Python 中不存在这个特定的操作！
I'm not familiar with any language that does have this operator. It is simply not needed.
我不熟悉任何具有此运算符的语言。它根本不需要。
As for your snippets:
至于你的片段：
if a == 0 or a > 0
if a == 0 or a > 0
It is exactly the same as if a >= 0
它与完全相同 if a >= 0
回答by Zentryn
You can use the equal or greater than operator:
您可以使用等于或大于运算符：
if a >= 0:
print(a)
回答by user9501848
Well python !>doesn't work.But
好吧，python!>不起作用。但是
if not a > 70:
print(' The number is Not bigger than 70')
else:
print(' The number is DEFINITELY bigger than 70')
this surprisingly works
这令人惊讶地有效
