Python 1005x132589 像素的图像尺寸太大。每个方向必须小于2^16
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Image size of 1005x132589 pixels is too large. It must be less than 2^16 in each direction
提问by debaonline4u
I am using matplotlib.pyplot to plot graph from Dataframe. Here I want to show the height of the bar upon each rectangle and am using Text(). And for normalising Y-Axis, I have taken Logscale upon Y-Axis. Below is my code, I am getting error
我正在使用 matplotlib.pyplot 从 Dataframe 绘制图形。在这里，我想在每个矩形上显示条的高度，并使用 Text()。为了标准化 Y 轴，我在 Y 轴上采用了 Logscale。下面是我的代码，我收到错误
Image size of 1005x132589 pixels is too large. It must be less than 2^16 in each direction
When I am not using plt.yscale('log')then code is working fine.
According to some suggestion I have restarted my Kernel too, but still getting this issue. Any suggestions regarding this is welcomed.
当我不使用时，plt.yscale('log')代码工作正常。根据一些建议，我也重新启动了我的内核，但仍然遇到这个问题。欢迎对此提出任何建议。
My Code:
我的代码：
`
# data collected to list.
list_alarms = df_region.alarmName
# list_east = df_region.EAST
list_west = df_region.WEST
list_north = df_region.NORTH
list_south = df_region.SOUTH
`
# 收集到列表的数据。list_alarms = df_region.alarmName # list_east = df_region.EAST list_west = df_region.WEST list_north = df_region.NORTH list_south = df_region.SOUTH
# X-ticks customization
N = len(list_alarms)
xpos = np.arange(N)
# this json file is used to update the style of the plot.
s = json.load(open('style.json'))
rcParams.update(s)
# Graph customize
plt.rcParams['figure.figsize'] = (15,8)
plt.xlabel('AlarmNames at different Regions')
plt.ylabel('Frequency for alarms in MNG-PAN devices')
plt.title('Alarm Generated by MNG-PAN Device at different Regions')
plt.xticks(xpos,list_alarms, rotation = 280)
# bar1 = plt.bar(xpos - 0.3,list_east, width = 0.2, label = 'EAST',
color = '#3154C8')
bar2 = plt.bar(xpos - 0.1, list_west, label = 'WEST', color =
'#FF9633')
bar3 = plt.bar(xpos + 0.1, list_north, label = 'NORTH', color =
'#12B794')
bar4 = plt.bar(xpos + 0.3, list_south, label = 'SOUTH', color =
'#EF6FE3')
plt.yscale('log')
plt.legend()
def autolabel(rects):
for rect in rects:
height = rect.get_height()
if height < 10000:
plt.text(rect.get_x() + rect.get_width()/2., 1.05*height,
'%d'%int(height),
ha = 'center', va = 'bottom', rotation = 90,
fontsize=9)
# # autolabel(bar1)
autolabel(bar2)
autolabel(bar3)
autolabel(bar4)
plt.show()
`
`
I am using Jupyter Notebook, Pandas, Python3.
我正在使用 Jupyter Notebook、Pandas、Python3。
回答by ???
Check your location variables at plt.textline in autolabel definition. I had a same problem and I found that y variable which I gave to plt.textfunction is too large compared to the value of my dataset of plot.
plt.text在自动标签定义中检查您的位置变量。我遇到了同样的问题，我发现我给plt.text函数的y 变量与我的绘图数据集的值相比太大了。
回答by Phoenix
You can adujust pixels and update your update_datalim()
您可以调整像素并更新您的 update_datalim()
fig = plt.figure(1, figsize=(8, 14), frameon=False, dpi=100)
fig.add_axes([0, 0, 1, 1])
ax = plt.gca()
corners = ((x1, y1), (x2, y2))
ax.update_datalim(corners)
回答by Reinier Koops
Another possible explanation could be that one of your y-axis values is zero. Thus you could edit your autolabel function into something like this:
另一种可能的解释可能是您的 y 轴值之一为零。因此，您可以将自动标签功能编辑为如下所示：
def autolabel(rects):
for rect in rects:
height = rect.get_height()
if (height != 0):
ax.annotate('{}'.format(height),
xy=(rect.get_x() + rect.get_width() / 2, height),
xytext=(0, 3), # 3 points vertical offset
textcoords="offset points",
ha='center', va='bottom')
