Javascript 之后用 PHP 函数确认
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Javascript confirm with PHP function afterward
提问by Catia
I would like a way to have a confirm box pop up when a user clicks "delete" to remove a record.
我想要一种在用户单击“删除”以删除记录时弹出确认框的方法。
Something like:
就像是：
<script language="JavaScript" type="text/javascript" >
function confirmDelete() {
if(confirm("Would you like to delete the selected products?")) {
<?php
$allCheckBoxId = $_POST['checkbox'];
array_map ('mysql_real_escape_string', $allCheckBoxId);
$ids = implode(",", $allCheckBoxId);
$sql = "DELETE FROM products WHERE `id` IN ($ids)";
mysql_query($sql);
?>
}
}
</script>
With an onclick:
通过点击：
echo "<input type='submit' name='submit' value='Delete' onclick='confirmDelete()' />";
But I know it's not possible to be using Javascript & PHP together like this. Is there another way to do this? Maybe PHP has its own kind of confirm? Please give any ideas!
但我知道不可能像这样一起使用 Javascript 和 PHP。有没有另一种方法可以做到这一点？也许PHP有自己的确认方式？请给出任何想法！
Thank you.
谢谢你。
回答by Jules
It is pretty easy to make use of AJAX for this case. Simply place your PHP in the scriptDelete.phpfile and make sure you pass the proper arguments and their values in the dataproperty. For this example I just pass an idof 5.
在这种情况下使用 AJAX 非常容易。只需将您的 PHP 放在scriptDelete.php文件中，并确保在data属性中传递正确的参数及其值。在这个例子中，我传递一个ID的5。
<script type="text/javascript">
function confirmDelete() {
if (confirm('Are you sure you want to delete this?')) {
//Make ajax call
$.ajax({
url: "scriptDelete.php",
type: "POST",
data: {id : 5},
dataType: "html",
success: function() {
alert("It was succesfully deleted!");
}
});
}
}
</script>
<input type='submit' name='submit' value='Delete' onclick='return confirmDelete()' />
Another way would be to post the form back to its own page like:
另一种方法是将表单发布回其自己的页面，例如：
<form method="post" action="yourpage.php">
<input type="submit" name="submit" value="delete" onclick="return confirm('Are you sure you want to delete this?')" />
</form>
So you simply post the form back to yourpage.phpand on top of this page you do something like:
因此，您只需将表单发回yourpage.php并在此页面的顶部执行以下操作：
<?php
//Means the form was submitted
if ($_POST['submit']) {
$id = $_POST['idToDelete'];
$query = "DELETE FROM products WHERE id = " . mysql_real_escape_string($id);
mysql_query($query) or die(mysql_error());
}
?>
回答by Mitch Grande
You should move the event to the form, and use onsubmit="confirmDelete()". If you return false within the ConfirmDelete function, the form submit is cancelled. If you return true, the form will get submitted like normal, and you can process it like a regular form on the server side.
您应该将事件移动到表单中，并使用 onsubmit="confirmDelete()"。如果您在 ConfirmDelete 函数中返回 false，则表单提交将被取消。如果您返回 true，表单将像正常一样提交，您可以像服务器端的常规表单一样处理它。
<script type="text/javascript">
function confirmDelete() {
return window.confirm("Are you sure you want to delete this record?");
}
</script>
<form action="myDelete.php" onsubmit="confirmDelete()">
....inputs
<input type="submit" name="submit" value="Delete">
</form>
Then have regular processing code on the server side
然后在服务器端有规律的处理代码
回答by Faisal
Easy way to confirm, instead of creating whole new function. Do this
确认的简单方法，而不是创建全新的功能。做这个
<input type="submit" name="Delete" onClick='return confirm("Sure you want Delete this Page?")' />
this will exactly respond the same way.
这将完全以相同的方式响应。
回答by Xuntar
The easiest way is to do a javascript function before you submit. If you click on false, the return will be false and it will not be submitted:
最简单的方法是在提交之前执行 javascript 函数。如果点击false，则返回false，不会提交：
<form action="something.php" onSubmit="return confirm('Are you sure?');" method="post">
// Fields
// Fields
<input type="submit" name="Submit" class="button" value="Submit">
</form>
回答by Brendon Dugan
Ajax. Place your php in a separate file, and use ajax to send it the id you want to use in your query. I recommend jQuery .post
阿贾克斯。将您的 php 放在一个单独的文件中，并使用 ajax 将您要在查询中使用的 id 发送给它。我推荐jQuery .post
