xml 使用 xpath 选择具有一组多个属性/值的元素
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use xpath to select elements with a set of multiple attributes/values
提问by Hector
I have an XML document that i need to strip out particular pieces of data
我有一个 XML 文档，我需要去除特定的数据片段
the xml document has a structure as follows:-
xml 文档的结构如下：-
<a>
<b select='yes please'>
<c d='text1' e='text11'/>
<c d='text2' e='text12'/>
<c d='text3' e='text13'/>
<c d='text4' e='text14'/>
<c d='text5' e='text15'/>
</b>
</a>
<a>
<b select='no thanks'>
<c d='text1' e='text21'/>
<c d='text3' e='text23'/>
<c d='text5' e='text25'/>
</b>
</a>
<a>
<b select='yes please'>
<c d='text1' e='text31'/>
<c d='text2' e='text32'/>
<c d='text3' e='text33'/>
<c d='text4' e='text34'/>
<c d='text5' e='text35'/>
</b>
</a>
<a>
<b select='no thanks'>
<c d='text4' e='text41'/>
<c d='text3' e='text43'/>
<c d='text5' e='text45'/>
</b>
</a>
i need to select only those /a/b element groups that have d attribute = 'text1' and d attribute = 'text4', once i have identified these sub documents i want to get the value of the e attributes with d attribute value 'text5'
我只需要选择那些具有 d 属性 = 'text1' 和 d 属性 = 'text4' 的 /a/b 元素组，一旦我确定了这些子文档，我想获取具有 d 属性值的 e 属性的值'文本5'
hope thats clear
希望这很清楚
Cheers
干杯
DD
DD
回答by Kirill Polishchuk
You can use this XPath:
您可以使用此 XPath：
//a[b/c/@d = 'text1' and b/c/@d = 'text4']/b/c[@d = 'text5']/@e
It will select e='text15'and e='text35'of 1st and 3rd a/b
这将选择e='text15'与e='text35'第一和第三的a/b
XSLT:
XSLT：
<xsl:template match="//a[b/c/@d = 'text1' and b/c/@d = 'text4']/b/c[@d = 'text5']">
<xsl:value-of select="@e"/>
</xsl:template>
回答by Michael Kay
i need to select only those /a/b element groups that have d attribute = 'text1' and d attribute = 'text4', once i have identified these sub documents i want to get the value of the e attributes with d attribute value 'text5'
hope thats clear
我只需要选择那些具有 d 属性 = 'text1' 和 d 属性 = 'text4' 的 /a/b 元素组，一旦我确定了这些子文档，我想获取具有 d 属性值的 e 属性的值'文本5'
希望这很清楚
Yes, it's so clear the translation into XPath is almost mechanical
是的，很明显，转换成 XPath 几乎是机械的
(: those /a/b element groups :) a/b
(: that have d attribute = 'text1' :) [c/@d='text1']
(: and d attribute = 'text4' :) [c/@d='text4']
(: and .. i want to get the value of the e attributes
with d attribute value 'text5' :) / c[@d='text5'] / @e
回答by Emiliano Poggi
You can use a single template to match the required group, and then you get the value of the required attributes:
您可以使用单个模板来匹配所需的组，然后获取所需属性的值：
<xsl:template match="/*/a/b[c[@d='text1'] and c[@d='text4']]">
<xsl:value-of select="c[@d='text5']/@e"/>
</xsl:template>
assuming:
假设：
<root>
<a>
<b select='yes please'>
<c d='text1' e='text11'/>
<c d='text2' e='text12'/>
<c d='text3' e='text13'/>
<c d='text4' e='text14'/>
<c d='text5' e='text15'/>
</b>
</a>
<a>
<b select='no thanks'>
<c d='text1' e='text21'/>
<c d='text3' e='text23'/>
<c d='text5' e='text25'/>
</b>
</a>
<a>
<b select='yes please'>
<c d='text1' e='text31'/>
<c d='text2' e='text32'/>
<c d='text3' e='text33'/>
<c d='text4' e='text34'/>
<c d='text5' e='text35'/>
</b>
</a>
<a>
<b select='no thanks'>
<c d='text4' e='text41'/>
<c d='text3' e='text43'/>
<c d='text5' e='text45'/>
</b>
</a>
</root>
the output will be text15and text35.
输出将是text15和text35。
回答by Dimitre Novatchev
Use this single XPath expression:
使用这个单一的 XPath 表达式：
/*/a/b[c/@d='text1' and c/@d='text4']
/c[@d='text5']
/@e
