使用 XSLT 将 XML 文件转换为另一个 XML 文件
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Converting XML file to another XML file using XSLT
提问by shavinda
XML file 1:
XML 文件 1：
<?xml version="1.0"?>
<rentalProperties>
<property contact ="1">
<type>House </type>
<price>420</price>
<address>
<streetNo>1</streetNo>
<street>Wavell Street</street>
<suburb>Box Hill</suburb>
<state>VIC</state>
<zipcode>3128</zipcode>
</address>
<numberOfBedrooms>3</numberOfBedrooms>
<numberOfBathrooms>1</numberOfBathrooms>
<garage>1</garage>
</property>
XML file 2:
XML 文件 2：
<?xml version="1.0"?>
<rentalProperties>
<property contact ="1">
<type>House </type>
<price>420</price>
<address>1 wavell street,Box Hill,VIC,Australia</address>
<numberOfBedrooms>3</numberOfBedrooms>
<numberOfBathrooms>1</numberOfBathrooms>
<garage>1</garage>
</property>
How should i convert xml file 1 to xml fle 2 using xslt? i want to represent the address as the single line and add a new attribute [country- Australia] to end of the line. i did the rest of it . i'm struggling with address line
我应该如何使用 xslt 将 xml 文件 1 转换为 xml 文件 2？我想将地址表示为单行，并在行尾添加一个新属性 [country-Australia]。我做了剩下的。我正在为地址行苦苦挣扎
XSLT file:
XSLT 文件：
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" type="text/css" href="style.css">
<xsl:template match="/">
<rentalProperties>
<property>
<xsl:attribute name="contact"><xsl:value-of select='@contact'/></xsl:attribute>
<type><xsl:value-of select="type"/></type>
<price><xsl:value-of select="price"/></price>
<numberOfBedrooms><xsl:value-of select="numberOfBedrooms"/></numberOfBedrooms>
<numberOfBathrooms><xsl:value-of select="numberOfBathrooms"/></numberOfBathrooms>
<garage><xsl:value-of select="garage"/></garage>
</property>
</rentalProperties>
</xsl:template>
</xsl:stylesheet>
回答by Dimitre Novatchev
This transformation:
这种转变：
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="address">
<xsl:copy>
<xsl:value-of select=
"concat(streetNo, ' ', street, ',',
suburb,',', state,', Australia')
"/>
</xsl:copy>
</xsl:template>
<xsl:template match="address/node()"/>
</xsl:stylesheet>
when applied on the provided XML document:
当应用于提供的 XML 文档时：
<rentalProperties>
<property contact ="1">
<type>House </type>
<price>420</price>
<address>
<streetNo>1</streetNo>
<street>Wavell Street</street>
<suburb>Box Hill</suburb>
<state>VIC</state>
<zipcode>3128</zipcode>
</address>
<numberOfBedrooms>3</numberOfBedrooms>
<numberOfBathrooms>1</numberOfBathrooms>
<garage>1</garage>
</property>
</rentalProperties>
produces the wanted, correct result:
产生想要的、正确的结果：
<rentalProperties>
<property contact="1">
<type>House </type>
<price>420</price>
<address>1 Wavell Street,Box Hill,VIC, Australia</address>
<numberOfBedrooms>3</numberOfBedrooms>
<numberOfBathrooms>1</numberOfBathrooms>
<garage>1</garage>
</property>
</rentalProperties>
Explanation: Using and overriding the identity rule.
说明：使用和覆盖身份规则。
回答by Osiris76
You could introduce a new template for the address block using
您可以使用为地址块引入一个新模板
<xsl:template match="address">
<xsl:value-of select="streetNo" />
<xsl:text> </xsl:text>
<xsl:value-of select="street" />
<xsl:text>,</xsl:text>
<xsl:value-of select="suburb" />
<xsl:text>,</xsl:text>
<xsl:value-of select="state" />
<xsl:text>,</xsl:text>
<xsl:value-of select="zipcode" />
</xsl:template>
and call it with
并调用它
<xsl:apply-templates select="address" />
before the <numberOfBedrooms>element. This can also be done using the concatfunction, whereas the correct syntax I don't remember right now.
在<numberOfBedrooms>元素之前。这也可以使用该concat函数来完成，而我现在不记得正确的语法。
回答by actionshrimp
You can try something like:
您可以尝试以下操作：
<address>
<xsl:for-each select="address/*">
<xsl:value-of select="."/>,
</xsl:for-each>
Australia
</address>
This loops over all the children of the address tag in xml1.
这将遍历 xml1 中地址标记的所有子项。
回答by raj
<rentalProperties>
<property contact="1">
<type>House </type>
<price>420</price>
<address>1 Wavell Street,Box Hill,VIC,3128</address>
<numberOfBedrooms>3</numberOfBedrooms>
<numberOfBathrooms>1</numberOfBathrooms>
<garage>1</garage>
</property>
</rentalProperties>
