在android中获取imageview内的触摸位置
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Get the touch position inside the imageview in android
提问by Manikandan
I have a imageview in my activity and I am able to get the position where the user touch the imageview, through onTouchListener. I placed another image where the user touch over that image. I need to store the touch position(x,y), and use it in another activity, to show the tags. I stored the touch position in the first activity. In the first activity, my imageview at the top of the screen. In the second activity its at the bottom of the screen. If I use the position stored from the first acitvity, it place the tag image at the top, not on the imageview, where I previously clicked in the first activity. Is there anyway to get the position inside the imageview.
我的活动中有一个图像视图，我能够通过 onTouchListener 获取用户触摸图像视图的位置。我在用户触摸该图像的位置放置了另一个图像。我需要存储触摸位置（x，y），并在另一个活动中使用它来显示标签。我在第一个活动中存储了触摸位置。在第一个活动中，我的图像视图位于屏幕顶部。在第二个活动中，它位于屏幕底部。如果我使用从第一个活动存储的位置，它会将标签图像放在顶部，而不是在我之前在第一个活动中单击的图像视图上。反正有没有得到图像视图中的位置。
FirstActivity:
第一活动：
cp.setOnTouchListener(new OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
x = (int) event.getX();
y = (int) event.getY();
Log.v("touched x val of cap img >>", x + "");
Log.v("touched y val of cap img >>", y + "");
tag.setVisibility(View.VISIBLE);
int[] viewCoords = new int[2];
cp.getLocationOnScreen(viewCoords);
int imageX = x - viewCoords[0]; // viewCoods[0] is the X coordinate
int imageY = y - viewCoords[1]; // viewCoods[1] is the y coordinate
Log.v("Real x >>>",imageX+"");
Log.v("Real y >>>",imageY+"");
RelativeLayout rl = (RelativeLayout) findViewById(R.id.lay_lin);
ImageView iv = new ImageView(Capture_Image.this);
Bitmap bm = BitmapFactory.decodeResource(getResources(),
R.drawable.tag_icon_32);
iv.setImageBitmap(bm);
RelativeLayout.LayoutParams params = new RelativeLayout.LayoutParams(
RelativeLayout.LayoutParams.WRAP_CONTENT, RelativeLayout.LayoutParams.WRAP_CONTENT);
params.leftMargin = x;
params.topMargin = y;
rl.addView(iv, params);
Intent intent= new Intent(Capture_Image.this,Tag_Image.class);
Bundle b=new Bundle();
b.putInt("xval", imageX);
b.putInt("yval", imageY);
intent.putExtras(b);
startActivity(intent);
return false;
}
});
In TagImage.java I used the following:
在 TagImage.java 中，我使用了以下内容：
im = (ImageView) findViewById(R.id.img_cam22);
b=getIntent().getExtras();
xx=b.getInt("xval");
yy=b.getInt("yval");
im.setOnTouchListener(new OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
int[] viewCoords = new int[2];
im.getLocationOnScreen(viewCoords);
int imageX = xx + viewCoords[0]; // viewCoods[0] is the X coordinate
int imageY = yy+ viewCoords[1]; // viewCoods[1] is the y coordinate
Log.v("Real x >>>",imageX+"");
Log.v("Real y >>>",imageY+"");
RelativeLayout rl = (RelativeLayout) findViewById(R.id.lay_lin);
ImageView iv = new ImageView(Tag_Image.this);
Bitmap bm = BitmapFactory.decodeResource(getResources(),
R.drawable.tag_icon_32);
iv.setImageBitmap(bm);
RelativeLayout.LayoutParams params = new RelativeLayout.LayoutParams(
30, 40);
params.leftMargin =imageX ;
params.topMargin = imageY;
rl.addView(iv, params);
return true;
}
});
回答by Adam L. Mónos
You can get the top left corner of your view as follows:
您可以按如下方式获取视图的左上角：
int[] viewCoords = new int[2];
imageView.getLocationOnScreen(viewCoords);
From this and the touch coordinates you can calculate the point inside the ImageView:
从这个和触摸坐标你可以计算出 ImageView 内的点：
int touchX = (int) event.getX();
int touchY = (int) event.getY();
int imageX = touchX - viewCoords[0]; // viewCoords[0] is the X coordinate
int imageY = touchY - viewCoords[1]; // viewCoords[1] is the y coordinate
回答by Shantanu Khond
Add these lines to ImageView
将这些行添加到 ImageView
android:scaleType="fitXY"
and
和
android:adjustViewBounds="true"
to your image view it is because image are not having their original dimensions in IV
对于您的图像视图，这是因为图像在 IV 中没有其原始尺寸
