php 在php中动态构建json数组
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build json array in php dynamically
提问by Mike
I can create simple json objects like this:
我可以像这样创建简单的 json 对象:
$d = array('item' => "$name" ,'rate' => "$rating");
But what if I want to build an array of items and do it dynamically since I am building it from a db query?
但是,如果我想构建一个项目数组并动态执行它,因为我是从 db 查询构建它呢?
Update:
更新:
Let me be more specific I know I have to do:
让我更具体地说明我知道我必须这样做:
$jsonCode = json_encode($d);
which will create a json object with an item and rate field. But I want multiple json objects in a json array when i encode it.
这将创建一个带有项目和费率字段的 json 对象。但是当我对它进行编码时,我想要一个 json 数组中的多个 json 对象。
What I want json wise is something like this:
我想要 json 明智的是这样的:
[{"item":"toy","rating":"baz" },{"item":"bike","rating":"2.3" }, {"item":"juice","rating":"1.3" }]
回答by Felix Kling
But I want multiple json objects in a json array when i encode it.
但是当我对它进行编码时,我想要一个 json 数组中的多个 json 对象。
Then create an array of arraysand pass it to json_encode
. The documentation about arraysexplains how to add elements to an array, in the section Creating/modifying with square bracket syntax.
然后创建一个数组数组并将其传递给json_encode
. 有关数组的文档在使用方括号语法创建/修改部分中解释了如何向数组添加元素。
Associative arrays, like the one you already have, will be encoded as objects, "normal" arrays (arrays with consecutive numerical keys) will be encoded as arrays.
关联数组,就像您已有的数组一样,将被编码为对象,“普通”数组(具有连续数字键的数组)将被编码为数组。
Example:
例子:
$d = array();
// This appends a new element to $d, in this case the value is another array
$d[] = array('item' => "$name" ,'rate' => "$rating");
$json = json_encode($d);
回答by Barmar
This will create a multi-dimensional array from your database query, and then encode it as JSON.
这将从您的数据库查询创建一个多维数组,然后将其编码为 JSON。
$d = array();
while ($row = $stmt->fetch_assoc()) {
$d[] = $row;
}
$json = json_encode($d);
Each $row
will be an associative array of the data returned from the database. Assigning it to $d[]
adds it as an indexed element of that container array.
每个$row
都是从数据库返回的数据的关联数组。将它分配给$d[]
添加它作为该容器数组的索引元素。
回答by Liam Sorsby
Why not create your array as you just have done but then pass the array through json_encode
?
为什么不像刚才那样创建数组,然后将数组传递给它json_encode
呢?
If you want a multi-dimensional array, try
如果你想要一个多维数组,试试
$array[] = array("key1" => value1, "key2" => value2);
回答by Techie
What you can do is create a php array dynamically as you want then covert it into a json array as below.
您可以做的是根据需要动态创建一个 php 数组,然后将其转换为 json 数组,如下所示。
$json_array = json_encode($array);
Keep in mind that what you have provided is not a json array
请记住,您提供的不是 json 数组