bash 是否可以在函数体中获取函数名称？
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Is it possible to get the function name in function body?
提问by Yun Huang
In BASH, is it possible to get the function name in function body? Taking following codes as example, I want to print the function name "Test" in its body, but "$0" seems to refer to the script name instead of the function name. So how to get the function name?
在 BASH 中，是否可以在函数体中获取函数名称？以下面的代码为例，我想在它的主体中打印函数名称“Test”，但“$0”似乎是指脚本名称而不是函数名称。那么如何获取函数名呢？
#!/bin/bash
function Test
{
if [ $# -lt 1 ]
then
# how to get the function name here?
echo " FUNCNAME
An array variable containing the names of all shell functions
currently in the execution call stack. The element with index 0
is the name of any currently-executing shell function. The bot‐
tom-most element is "main". This variable exists only when a
shell function is executing. Assignments to FUNCNAME have no
effect and return an error status. If FUNCNAME is unset, it
loses its special properties, even if it is subsequently reset.
num" 1>&2
exit 1
fi
local num=""
echo "${num}"
}
# the correct function
Test 100
# missing argument, the function should exit with error
Test
exit 0
回答by FatalError
Try ${FUNCNAME[0]}. This array contains the current call stack. To quote the man page:
试试${FUNCNAME[0]}。此数组包含当前调用堆栈。引用手册页：
$ ./sample
foo
bar
$ cat sample
#!/bin/bash
foo() {
echo ${FUNCNAME[ 0 ]} # prints 'foo'
echo ${FUNCNAME[ 1 ]} # prints 'bar'
}
bar() { foo; }
bar
回答by William Pursell
The name of the function is in ${FUNCNAME[ 0 ]}FUNCNAME is an array containing all the names of the functions in the call stack, so:
函数名在${FUNCNAME[ 0 ]}FUNCNAME 中是一个数组，包含调用堆栈中所有函数的名称，因此：
