PHP。是否可以将 array_column 与对象数组一起使用
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PHP. Is it possible to use array_column with an array of objects
提问by Eldar Rakhimberdin
Is it possible to pass in array_columnan array of objects?
I have implemented ArrayAccess interface, but it has no effect.
Should I implement another one?
是否可以传入array_column对象数组？
我已经实现了 ArrayAccess 接口，但是没有效果。
我应该实施另一个吗？
class Foo implements ArrayAccess {
public $Id, $Title;
public function offsetExists($offset)
{
return isset($this->{$offset});
}
public function offsetGet($offset)
{
return $this->{$offset};
}
public function offsetSet($offset, $value)
{
$this->{$offset} = $value;
}
public function offsetUnset($offset)
{
unset($this->{$offset});
}
}
$object = new \Foo();
$object->Id = 1;
$object->Title = 'Test';
$records = array(
$object,
array(
'Id' => 2,
'Title' => 'John'
)
);
var_dump(array_column($records, 'Title')); // array (size=1) 0 => string 'John' (length=4)
回答by Daniel W.
PHP 5
PHP 5
array_columndoesn't work with an array of objects. Use array_mapinstead:
array_column不适用于对象数组。使用array_map来代替：
$titles = array_map(function($e) {
return is_object($e) ? $e->Title : $e['Title'];
}, $records);
PHP 7
PHP 7
array_column()
array_column()
The function now supports an array of objects as well as two-dimensional arrays. Only public properties are considered, and objects that make use of
__get()for dynamic properties must also implement__isset().
该函数现在支持对象数组和二维数组。只考虑公共属性，使用
__get()动态属性的对象也 必须实现__isset().
See https://github.com/php/php-src/blob/PHP-7.0.0/UPGRADING#L629- Thanks to Bellfor the hint!
请参阅https://github.com/php/php-src/blob/PHP-7.0.0/UPGRADING#L629- 感谢Bell的提示！
回答by cgaldiolo
Is it possible to pass in array_column an array of objects?
是否可以在 array_column 中传递一个对象数组？
PHP 7
PHP 7
Yes, see http://php.net/manual/en/function.array-column.php
是的，请参阅http://php.net/manual/en/function.array-column.php
PHP 5 >= 5.5.0
PHP 5 >= 5.5.0
In PHP 5 array_columndoes not work with an array of objects. You can try with:
在 PHP 5array_column中不适用于对象数组。您可以尝试：
// object 1
$a = new stdClass();
$a->my_string = 'ciao';
$a->my_number = 10;
// object 2
$b = new stdClass();
$b->my_string = 'ciao b';
$b->my_number = 100;
// array of objects
$arr_o = array($a,$b);
// using array_column with an array of objects
$result = array_column(array_map(function($o){return (array)$o;},$arr_o),'my_string');
PS: for clarity I prefer to not use array_columnand use array_map with an anonymous function
PS：为了清楚起见，我更喜欢不使用array_column和使用带有匿名函数的array_map
$result = array_map(function($o){ return $o->my_string; }, $arr_o);
or a simple foreach
或者一个简单的 foreach
$result = array();
foreach($arr_o as $o) {
$result[] = $o->my_string;
}
回答by Tofandel
Here is a function that will work on both php7 and php5
这是一个适用于 php7 和 php5 的函数
function array_column_portable($array, $key) {
return array_map(function($e) use ($key) {
return is_object($e) ? $e->$key : $e[$key];
}, $array);
}
You can then use it as you use array_columnin php7
然后您可以像在 php7 中使用array_column一样使用它
回答by Igor Okto
Possible solution is prepare that array of objects:
可能的解决方案是准备该对象数组：
$objectsList = [];
foreach ($objs as $obj) {
$objectsList[] = (array)$obj;
}
$propList = array_column($objectsList, 'prop');
回答by yckart
While it's not possible to use array_columnon child-objects, you can cast them to arrays. This is of course not the way to go, but it's a way.
虽然无法array_column在子对象上使用，但您可以将它们转换为数组。这当然不是要走的路，但这是一条路。
Using array_map/get_object_vars(doesn't not work in your case, due the containing array)
使用array_map/get_object_vars（在您的情况下不起作用，因为包含数组）
array_column(array_map('get_object_vars', $thingy), 'property');
Using json_decode/json_encode
使用 json_decode/json_encode
array_column(json_decode(json_encode($thingy), true), 'property');
Note: Using json brings not the same result as using a true recursive function. You'll lose protected and private properties of the object. But in some situations its fine.
注意：使用 json 与使用真正的递归函数带来的结果不同。您将丢失对象的受保护和私有属性。但在某些情况下它很好。
function object_to_array($object) {
if (is_object($object)) $object = get_object_vars($object);
return is_array($object) ? array_map(__FUNCTION__, $object) : $object;
}回答by Nikunj Dhimar
For future Visitor.
对于未来的访客。
$arrayColumnData = array_map(function($e) {
return is_object($e) ? $e->your_column : $e['your_column'];
}, $yourArray);
Thanks.
谢谢。
