以毫秒为单位将python日期时间转换为时间戳
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Convert python datetime to timestamp in milliseconds
提问by Tom
How to convert a human readable time with the format 20.12.2016 09:38:42,76to Unix timestamps in milliseconds? I found a lot of similar questions, but didn't found this specific question/answer.
如何以毫秒为单位将格式20.12.2016 09:38:42,76为人类可读的时间转换为 Unix 时间戳？我发现了很多类似的问题，但没有找到这个特定的问题/答案。
回答by Milo
In Python 3 this can be done in 2 steps:
在 Python 3 中，这可以通过 2 个步骤完成：
- Convert timestring to
datetimeobject - Multiply the timestamp of the
datetimeobject by 1000 to convert it to milliseconds.
- 将时间字符串转换为
datetime对象 - 将
datetime对象的时间戳乘以1000 以将其转换为毫秒。
For example like this:
例如像这样：
from datetime import datetime
dt_obj = datetime.strptime('20.12.2016 09:38:42,76',
'%d.%m.%Y %H:%M:%S,%f')
millisec = dt_obj.timestamp() * 1000
print(millisec)
Output:
输出：
1482223122760.0
strptimeaccepts your timestring and a format string as input. The timestring (first argument) specifies whatyou actually want to convert to a datetimeobject. The format string (second argument) specifies the actual formatof the string that you have passed.
strptime接受您的时间字符串和格式字符串作为输入。该TIMESTRING（第一个参数）指定什么你真的想转换为datetime对象。格式字符串（第二个参数）指定您传递的字符串的实际格式。
Here is the explanation of the format specifiers from the official documentation:
以下是官方文档中对格式说明符的解释：
%d- Day of the month as a zero-padded decimal number.%m- Month as a zero-padded decimal number.%Y- Year with century as a decimal number%H- Hour (24-hour clock) as a zero-padded decimal number.%M- Minute as a zero-padded decimal number.%S- Second as a zero-padded decimal number.%f- Microsecond as a decimal number, zero-padded on the left.
%d- 以零填充的十进制数表示的月份中的某一天。%m- 以零填充的十进制数表示的月份。%Y- 以世纪为十进制数的年份%H- 小时（24 小时制）作为补零的十进制数。%M- 分钟作为用零填充的十进制数。%S- 第二个是用零填充的十进制数。%f- 微秒作为十进制数，在左侧补零。
回答by Matthew Cox
For Python2.7 - modifying MYGz's answer to not strip milliseconds:
对于 Python2.7 - 修改 MYGz 的答案不去除毫秒：
from datetime import datetime
d = datetime.strptime("20.12.2016 09:38:42,76", "%d.%m.%Y %H:%M:%S,%f").strftime('%s.%f')
d_in_ms = int(float(d)*1000)
print(d_in_ms)
print(datetime.fromtimestamp(float(d)))
Output:
输出：
1482248322760
2016-12-20 09:38:42.760000
回答by Maurice Meyer
You need to parse your time format using strptime.
您需要使用strptime解析您的时间格式。
>>> import time
>>> from datetime import datetime
>>> ts, ms = '20.12.2016 09:38:42,76'.split(',')
>>> ts
'20.12.2016 09:38:42'
>>> ms
'76'
>>> dt = datetime.strptime(ts, '%d.%m.%Y %H:%M:%S')
>>> time.mktime(dt.timetuple())*1000 + int(ms)*10
1482223122760.0
回答by MYGz
For Python2.7
对于 Python2.7
You can format it into seconds and then multiply by 1000 to convert to millisecond.
您可以将其格式化为秒，然后乘以 1000 以转换为毫秒。
from datetime import datetime
d = datetime.strptime("20.12.2016 09:38:42,76", "%d.%m.%Y %H:%M:%S,%f").strftime('%s')
d_in_ms = int(d)*1000
print(d_in_ms)
print(datetime.fromtimestamp(float(d)))
Output:
输出：
1482206922000
2016-12-20 09:38:42
回答by Ivan Klass
For those who searches for an answer without parsing and loosing milliseconds,
given dt_objis a datetime:
对于那些在不解析和丢失毫秒的情况下搜索答案的人，给出的dt_obj是一个日期时间：
python3 only, elegant
仅python3，优雅
int(dt_obj.timestamp() * 1000)
both python2 and python3 compatible:
python2和python3兼容：
import time
int(time.mktime(dt_obj.utctimetuple()) * 1000 + dt_obj.microsecond / 1000)
