如何从 Scala 的资源文件夹中读取文件?

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时间:2020-10-22 06:46:10  来源:igfitidea点击:

How to read files from resources folder in Scala?

scalascala-collections

提问by Pradip Karad

I have a folder structure like below:

我有一个如下所示的文件夹结构:

- main
-- java
-- resources 
-- scalaresources
--- commandFiles 

and in that folders I have my files that I have to read. Here is the code:

在那个文件夹中,我有我必须阅读的文件。这是代码:

def readData(runtype: String, snmphost: String, comstring: String, specificType:  String): Unit = {
  val realOrInvFile = "/commandFiles/snmpcmds." +runtype.trim // these files are under commandFiles folder, which I have to read. 
    try {
      if (specificType.equalsIgnoreCase("Cisco")) {
        val specificDeviceFile: String = "/commandFiles/snmpcmds."+runtype.trim+ ".cisco"
        val realOrInvCmdsList = scala.io.Source.fromFile(realOrInvFile).getLines().toList.filterNot(line => line.startsWith("#")).map{
          //some code 
        }
        val specificCmdsList = scala.io.Source.fromFile(specificDeviceFile).getLines().toList.filterNot(line => line.startsWith("#")).map{
          //some code
        }
      }
    } catch {
      case e: Exception => e.printStackTrace
    }
  }
}

回答by Andreas Neumann

Resources in Scala work exactly as they do in Java. It is best to follow the Java best practicesand put all resources in src/main/resourcesand src/test/resources.

Scala 中的资源与 Java 中的资源完全一样。最好遵循Java 最佳实践并将所有资源放入src/main/resourcessrc/test/resources.

Example folder structure:

示例文件夹结构:

testing_styles/
├── build.sbt
├── src
│?? └── main
│??     ├── resources
│??     │?? └── readme.txt

Scala 2.12.x && 2.13.x reading a resource

Scala 2.12.x && 2.13.x 读取资源

To read resources the object Sourceprovides the method fromResource.

为了读取资源,对象Source提供了方法fromResource

import scala.io.Source
val readmeText : Iterator[String] = Source.fromResource("readme.txt").getLines

reading resources prior 2.12 (still my favourite due to jar compatibility)

阅读 2.12 之前的资源(由于 jar 兼容性仍然是我的最爱)

To read resources you can use getClass.getResourceand getClass.getResourceAsStream.

要读取资源,您可以使用getClass.getResourcegetClass.getResourceAsStream

val stream: InputStream = getClass.getResourceAsStream("/readme.txt")
val lines: Iterator[String] = scala.io.Source.fromInputStream( stream ).getLines

nicer error feedback (2.12.x && 2.13.x)

更好的错误反馈(2.12.x && 2.13.x)

To avoid undebuggable Java NPEs, consider:

为避免无法调试的 Java NPE,请考虑:

import scala.util.Try
import scala.io.Source
import java.io.FileNotFoundException

object Example {

  def readResourceWithNiceError(resourcePath: String): Try[Iterator[String]] = 
    Try(Source.fromResource(resourcePath).getLines)
      .recover(throw new FileNotFoundException(resourcePath))
 }

good to know

很高兴知道

Keep in mind that getResourceAsStreamalso works fine when the resources are part of a jar, getResource, which returns a URL which is often used to create a file can lead to problems there.

请记住,当资源是jar 的一部分时,getResourceAsStream也可以正常工作,getResource返回一个通常用于创建文件的 URL 可能会导致问题。

in Production

生产中

In production code I suggest to make sure that the source is closed again.

在生产代码中,我建议确保再次关闭源代码。

回答by Mohsen Kashi

For Scala >= 2.12, use Source.fromResource:

对于 Scala >= 2.12,使用Source.fromResource

scala.io.Source.fromResource("located_in_resouces.any")

回答by freedev

Onliner solution for Scala >= 2.12

Scala >= 2.12 的在线解决方案

val source_html = Source.fromResource("file.html").mkString

回答by Sri

import scala.io.Source

object Demo {

  def main(args: Array[String]): Unit = {

    val fileStream = getClass.getResourceAsStream("/json-sample.js")
    val lines = Source.fromInputStream(fileStream).getLines
    lines.foreach(line => println(line))

  }

}

enter image description here

在此处输入图片说明

EDIT: Credit to the original author. Refer the full blog here

编辑:感谢原作者。请参阅此处的完整博客

回答by Tony Fraser

For Scala 2.11, if getLines doesn't do exactly what you want you can also copy the a file out of the jar to the local file system.

对于Scala 2.11,如果 getLines 没有完全按照您的要求执行,您还可以将 a 文件从 jar 复制到本地文件系统。

Here's a snippit that reads a binary google .p12 format API key from /resources, writes it to /tmp, and then uses the file path string as an input to a spark-google-spreadsheetswrite.

这是一个片段,它从 /resources 读取二进制 google .p12 格式的 API 密钥,将其写入 /tmp,然后使用文件路径字符串作为spark-google-spreadsheets write的输入。

In the world of sbt-native-packagerand sbt-assembly, copying to local is also useful with scalatest binary file tests. Just pop them out of resources to local, run the tests, and then delete.

sbt-native-packagersbt-assembly的世界中,复制到本地对于 scalatest 二进制文件测试也很有用。只需将它们从资源中弹出到本地,运行测试,然后删除。

import java.io.{File, FileOutputStream}
import java.nio.file.{Files, Paths}

def resourceToLocal(resourcePath: String) = {
  val outPath = "/tmp/" + resourcePath
  if (!Files.exists(Paths.get(outPath))) {
    val resourceFileStream = getClass.getResourceAsStream(s"/${resourcePath}")
    val fos = new FileOutputStream(outPath)
    fos.write(
      Stream.continually(resourceFileStream.read).takeWhile(-1 !=).map(_.toByte).toArray
    )
    fos.close()
  }
  outPath
}

val filePathFromResourcesDirectory = "google-docs-key.p12"
val serviceAccountId = "[something]@drive-integration-[something].iam.gserviceaccount.com"
val googleSheetId = "1nC8Y3a8cvtXhhrpZCNAsP4MBHRm5Uee4xX-rCW3CW_4"
val tabName = "Favorite Cities"

import spark.implicits
val df = Seq(("Brooklyn", "New York"), 
          ("New York City", "New York"), 
          ("San Francisco", "California")).
          toDF("City", "State")

df.write.
  format("com.github.potix2.spark.google.spreadsheets").
  option("serviceAccountId", serviceAccountId).
  option("credentialPath", resourceToLocal(filePathFromResourcesDirectory)).
  save(s"${googleSheetId}/${tabName}")

回答by Dileep Dominic

The required file can be accessed as below from resource folder in scala

可以从scala的资源文件夹中访问所需的文件,如下所示

val file = scala.io.Source.fromFile(s"src/main/resources/app.config").getLines().mkString