Python _csv.Error：迭代器应该返回字符串，而不是字节（您是否以文本模式打开文件？）
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_csv.Error: iterator should return strings, not bytes (did you open the file in text mode?)
提问by ap306
At the start of my csv program:
在我的 csv 程序开始时：
import csv # imports the csv module
import sys # imports the sys module
f = open('Address Book.csv', 'rb') # opens the csv file
try:
reader = csv.reader(f) # creates the reader object
for row in reader: # iterates the rows of the file in orders
print (row) # prints each row
finally:
f.close() # closing
And the error is:
错误是：
for row in reader: # iterates the rows of the file in orders
_csv.Error: iterator should return strings, not bytes (did you open the file in text mode?)
采纳答案by Aaron Hall
Instead of this (and the rest):
而不是这个（和其余的）：
f = open('Address Book.csv', 'rb')
Do this:
做这个：
with open('Address Book.csv', 'r') as f:
reader = csv.reader(f)
for row in reader:
print(row)
The context manager means you don't need the finally: f.close(), because it will automatically close the file on an error, or on exiting the context.
上下文管理器意味着您不需要finally: f.close()，因为它会在出现错误或退出上下文时自动关闭文件。
回答by Garren S
The solution in this (duplicate?) question csv.Error: iterator should return strings, not byteshelped me:
这个（重复？）问题csv.Error: iterator should return strings, not bytes 中的解决方案帮助了我：
f = open('Address Book.csv', "rt")
or
或者
with open('Address Book.csv', "rt") as f:
or (using gzip)
或（使用 gzip）
import gzip
f = gzip.open('Address Book.csv', "rt")
or
或者
import gzip
gzip.open('Address Book.csv', "rt") as f:
