使用“浏览”按钮在 Tkinter 中显示文件的路径 - Python

Display Path of a file in Tkinter using "browse" Button - Python

提问by Jindil

I have been reading through several posts regarding to Browse button issues in Tkinter but I could not find my answer.

我一直在阅读有关 Tkinter 中浏览按钮问题的几篇文章，但找不到答案。

So I have wrote this code to get a directory path when clicking the browse button, and displaying this path in an entry field. It woks partly : a file browser window directly pops up when I run the script. I indeed get the path in the entry field but if I want then to change the folder using my Browse button it does not work.

因此，我编写了此代码以在单击浏览按钮时获取目录路径，并在输入字段中显示此路径。它部分起作用：当我运行脚本时，会直接弹出一个文件浏览器窗口。我确实在输入字段中获得了路径，但是如果我想使用浏览按钮更改文件夹，则它不起作用。

I dont want to have the browser poping up right from the start but only when I click on Browse ! Thanks for your answers

我不想让浏览器从一开始就弹出，但只有当我点击浏览时！谢谢你的回答

from Tkinter import *
from tkFileDialog import askdirectory

window = Tk() # user input window

MyText= StringVar()

def DisplayDir(Var):
    feedback = askdirectory()
    Var.set(feedback)

Button(window, text='Browse', command=DisplayDir(MyText)).pack()
Entry(window, textvariable = MyText).pack()
Button(window, text='OK', command=window.destroy).pack()

mainloop()

回答by Parviz Karimli

This is so easy -- you need to assign the path to a variable and then print it out:

这很简单——您需要将路径分配给一个变量，然后将其打印出来：

from tkinter import *
root = Tk()

def browsefunc():
    filename = filedialog.askopenfilename()
    pathlabel.config(text=filename)

browsebutton = Button(root, text="Browse", command=browsefunc)
browsebutton.pack()

pathlabel = Label(root)
pathlabel.pack()

P.S.:This is in Python 3. But the concept is same.

PS：这是在 Python 3 中。但概念是一样的。