Python 字典包含列表作为值 - 如何更新？
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Python Dictionary contains List as Value - How to update?
提问by Deepak
I have a dictionary which has value as a list.
我有一本字典，它具有列表的价值。
dictionary = {
'C1' : [10,20,30]
'C2' : [20,30,40]
}
Let's say I want to increment all the values in list of C1 by 10, how do I do it?
假设我想将 C1 列表中的所有值增加 10，我该怎么做？
dictionary.get('C1')gives me the list but how do i update it?
dictionary.get('C1')给了我列表，但我如何更新它？
采纳答案by Paolo Bergantino
>>> dictionary = {'C1' : [10,20,30],'C2' : [20,30,40]}
>>> dictionary['C1'] = [x+1 for x in dictionary['C1']]
>>> dictionary
{'C2': [20, 30, 40], 'C1': [11, 21, 31]}
回答by girasquid
Probably something like this:
大概是这样的：
original_list = dictionary.get('C1')
new_list = []
for item in original_list:
new_list.append(item+10)
dictionary['C1'] = new_list
回答by Utku Zihnioglu
dictionary["C1"]=map(lambda x:x+10,dictionary["C1"])
Should do it...
应该这样做...
回答by Gabe
An accessed dictionary value (a list in this case) is the original value, separate from the dictionary which is used to access it. You would increment the values in the list the same way whether it's in a dictionary or not:
访问的字典值（在本例中为列表）是原始值，与用于访问它的字典分开。无论是否在字典中，您都可以以相同的方式增加列表中的值：
l = dictionary.get('C1')
for i in range(len(l)):
l[i] += 10
回答by user5261053
why not just skip .get altogether and do something like this?:
为什么不完全跳过 .get 并做这样的事情？：
for x in range(len(dictionary["C1"]))
dictionary["C1"][x] += 10
回答by Loki
for i,j in dictionary .items():
if i=='C1':
c=[]
for k in j:
j=k+10
c.append(j)
dictionary .update({i:c})
