在 Python 2.4 中使用 urllib 解析查询字符串
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parse query string with urllib in Python 2.4
提问by Johannes Charra
Using Python2.4.5 (don't ask!) I want to parse a query string and get a dict in return. Do I have to do it "manually" like follows?
使用 Python2.4.5（不要问！）我想解析一个查询字符串并得到一个 dict 作为回报。我必须像下面这样“手动”做吗？
>>> qs = 'first=1&second=4&third=3'
>>> d = dict([x.split("=") for x in qs.split("&")])
>>> d
{'second': '4', 'third': '3', 'first': '1'}
Didn't find any useful method in urlparse.
中没有找到任何有用的方法urlparse。
回答by P?r Wieslander
You have two options:
您有两个选择：
>>> cgi.parse_qs(qs)
{'second': ['4'], 'third': ['3'], 'first': ['1']}
or
或者
>>> cgi.parse_qsl(qs)
[('first', '1'), ('second', '4'), ('third', '3')]
The values in the dict returned by cgi.parse_qs()are lists rather than strings, in order to handle the case when the same parameter is specified several times:
dict 中返回的值cgi.parse_qs()是列表而不是字符串，以便处理多次指定相同参数的情况：
>>> qs = 'tags=python&tags=programming'
>>> cgi.parse_qs(qs)
{'tags': ['python', 'programming']}
回答by Berry Tsakala
this solves the annoyance:
这解决了烦恼：
d = dict(urlparse.parse_qsl( qs ) )
personally i would expect there two be a built in wrapper in urlparse. in most cases i wouldn't mind to discards the redundant parameter if such exist
我个人希望在 urlparse 中有两个内置包装器。在大多数情况下，如果存在冗余参数，我不介意丢弃冗余参数
回答by Shariq
import urlparse
qs = 'first=1&second=4&third=3&first=0'
print dict(urlparse.parse_qsl(qs))
OR
print urlparse.parse_qs(qs)
