Python：创建多个列表
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Python : creating multiple lists
提问by zathizh
I'm trying to create multiple lists like the following:
我正在尝试创建多个列表，如下所示：
l1 = []
l2 = []
..
ln = []
Is there any way to do that?
有没有办法做到这一点？
采纳答案by A.J. Uppal
What you can do is use a dictionary:
你可以做的是使用字典：
>>> obj = {}
>>> for i in range(1, 21):
... obj['l'+str(i)] = []
...
>>> obj
{'l18': [], 'l19': [], 'l20': [], 'l14': [], 'l15': [], 'l16': [], 'l17': [], 'l10': [], 'l11': [], 'l12': [], 'l13': [], 'l6': [], 'l7': [], 'l4': [], 'l5': [], 'l2': [], 'l3': [], 'l1': [], 'l8': [], 'l9': []}
>>>
You can also create a list of lists using list comprehension:
您还可以使用列表理解创建列表列表：
>>> obj = [[] for i in range(20)]
>>> obj
[[], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], [], []]
>>>
回答by huu
Create a list of lists:
创建列表列表：
lists = []
n = 20
for i in range(n):
lists.append([])
print lists[0] # Prints []
print lists[19] # Prints []
回答by Akhzar Farhan
You can simply use a for loop to create n lists.
您可以简单地使用 for 循环来创建 n 个列表。
for i in range(10):
a_i = [i] #Stores the corresponding value of i in each a_i list.
print(a_i)
for i in range(10):
a_i = [i] #Stores the corresponding value of i in each a_i list.
print(a_i)
The variable a_i changes as i increments, so it becomes a_1, a_2, a_3 ... and so on.
变量 a_i 随着 i 的增加而变化，所以它变成了 a_1、a_2、a_3……等等。
回答by Cindyleee
You can use dictionary comprehension:
您可以使用字典理解：
obj = {i:[] for i in list(range(1,5))}
回答by Sanan Guliyev
Single line:
单线：
>>> lists = [[]] * 3
>>> lists[0]
[]
