脚本如何在 bash 中知道自己的名字？
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How a script know his own name in bash?
提问by Debugger
I launch script.sh and inside it i want to know what is his name
我启动 script.sh 并在里面我想知道他的名字是什么
Is there a standard procedure to know the scripts name ? the idea is to be able to extract the name from teh full path + name contained in $0
是否有知道脚本名称的标准程序？这个想法是能够从包含在的完整路径+名称中提取名称$0
Thanks
谢谢
回答by seamus
Yes, $0will always contain the name of the script. Use basename to extract the name.
是的，$0将始终包含脚本的名称。使用 basename 提取名称。
basename /some/really/long/dir/path/myscripts/coolscript.shwill print coolscript.sh
basename /some/really/long/dir/path/myscripts/coolscript.sh将打印 coolscript.sh
So in your script, you could do this:
所以在你的脚本中，你可以这样做：
my_scriptname="$(basename script="${0##*/}"
)"
回答by Paused until further notice.
Edit:
编辑：
This does the same thing as basename $0. It strips off the last slash and everything before it from $0using Bash's brace expansion.
这与basename $0. 它从$0使用 Bash 的大括号扩展中去除了最后一个斜线和它之前的所有内容。
回答by Vincent Robert
basename $0will give you the script name
basename $0会给你脚本名称
