bash 分叉两个进程并在第一个完成后杀死第二个
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Fork two processes and kill the second when the first is done
提问by User1
I want to create a bash script that will launch two processes and kill the second process when the first is done. Here's an example:
我想创建一个 bash 脚本，该脚本将启动两个进程并在第一个进程完成后终止第二个进程。下面是一个例子：
#fork first process producer& #fork second process consumer& #wait for producer to finish ... #kill the consumer ...
I have a feeling this can get ugly but has a very simple solution. Please help me fill in the blanks.
我有一种感觉，这可能会变得丑陋，但有一个非常简单的解决方案。请帮我填空。
回答by ndim
foo & pid_foo=$!
bar & pid_bar=$!
wait $pid_foo
kill $pid_bar
But perhaps you could just run foo | bar(if that happens to work with stdin/stdout handling).
但也许您可以直接运行foo | bar（如果这恰好适用于 stdin/stdout 处理）。
回答by frankc
#!/bin/bash
#enable job control in script
set -m
producer &
consumer &
fg %1
kill %2
