Bash 脚本未运行
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Bash script not running
提问by RohanK
I am trying to learn bash scripting and I'm using Ubuntu Linux. I have written a simple Bash file to count the number of files in current directory. I have written the following script in a file:
我正在尝试学习 bash 脚本，我正在使用 Ubuntu Linux。我编写了一个简单的 Bash 文件来计算当前目录中的文件数。我在文件中编写了以下脚本：
#! /bin/bash
ls -1 | wc -l
And saved the file with the name countFile.
并使用名称保存文件countFile。
But when I am trying to execute the script using ./countFileit is not executing. It shows the following error:
但是当我尝试使用./countFile它执行脚本时，它没有执行。它显示以下错误：
bash: ./countFile: Permission denied
The countFileis in my home directory so why I haven't the permission. Am I doing something wrong or missing some important thing? Moreover, the ls -1 | wc -lcommand gives me the correct output when I run it from the terminal.
So how can I run the countFilescript?
这countFile是在我的主目录中，所以为什么我没有权限。我做错了什么或错过了一些重要的事情吗？此外，ls -1 | wc -l当我从终端运行它时，该命令为我提供了正确的输出。
那么如何运行countFile脚本呢？
回答by Karthikeyan.R.S
While you are giving like this,
当你像这样给予时，
./countfile
You have to make that file as executable using chmod.
您必须使用chmod.
chmod +x countfile
Or else you can use the other interpreter like this.
否则，您可以像这样使用其他解释器。
sh countfile
回答by Bhuvanesh
while executing the file we need a execute permission for that file, we can change the permission or we just run as
在执行文件时，我们需要该文件的执行权限，我们可以更改权限，或者我们只是运行
. countfile
hew .will represent the current working shell
hew.将代表当前工作的 shell
