bash 使用bash终端命令打开目录和子目录中的所有文件？
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Open all files in a directory and subdirectories using bash terminal command?
提问by o_O
I have an alias where I can do open file1.type file2.typeor open *.type
我有一个别名，我可以在那里做open file1.type file2.type或open *.type
What I want is to be able to use this on all subdirectories of my current location. So if I'm in the parent directory and there are two child directories, running the command will be the same as running open file1.type file2.type child1/file1.type child2/file1.type
我想要的是能够在我当前位置的所有子目录上使用它。因此，如果我在父目录中并且有两个子目录，则运行该命令将与运行相同open file1.type file2.type child1/file1.type child2/file1.type
So something like open -? *.typeis what I'm looking for.
所以open -? *.type我正在寻找类似的东西。
回答by Ignacio Vazquez-Abrams
If running zsh or bash 4.x with the globstaroption set, **will match all directories recursively.
如果使用globstar设置的选项运行 zsh 或 bash 4.x ，**将递归匹配所有目录。
#!/bin/zsh
open **/*.type
...
...
#!/bin/bash
shopt -s globstar
open **/*.type
回答by Paul Hicks
findworks for this sort of functionality. Something like this:
find适用于这种功能。像这样的东西：
find . -type f -name \*.type -exec open {} \;
Or in this case, since openis an alias, you have to run the shell as the command:
或者在这种情况下，由于open是别名，您必须将 shell 作为命令运行：
find . -type f -name \*.type -exec bash -c open {} \;
