bash 如何在for循环中用值填充数组
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How to fill an array with values in a for loop
提问by Marta
I have to submit a script which adds two values within an for loop and puts every result in an array. I put together a script (which is not working) but I cannot figure out how to get it started.
我必须提交一个脚本，该脚本在 for 循环中添加两个值并将每个结果放入一个数组中。我整理了一个脚本（不起作用），但我不知道如何开始。
#!/bin/sh
val1=
val2=
for i in 10
do
${array[i]}='expr $val1+$val2'
$val1++
done
echo ${array[@]}
回答by konsolebox
Perhaps you mean this?
也许你是这个意思？
val1=
val2=
for i in {1..10}; do
array[i]=$(( val1 + val2 ))
(( ++val1 ))
done
echo "${array[@]}"
If you bash doesn't support {x..y}, use this format:
如果 bash 不支持{x..y}，请使用以下格式：
for (( i = 1; i <= 10; ++i )); do
Also simpler form of
还有更简单的形式
array[i]=$(( val1 + val2 ))
(( ++val1 ))
Is
是
(( array[i] = val1 + val2, ++val1 )) ## val1++ + val2 looks dirty
回答by Aleks-Daniel Jakimenko-A.
konsolebox's answeris right, but here are some alternatives:
konsolebox 的答案是正确的，但这里有一些替代方案：
val1=
val2=
for i in {0..9}; do
(( array[i]=val1 + val2 + i ))
done
echo "${array[@]}"
val1=
val2=
for (( i=val1 + val2; i < val1 + val2 + 10; i++ )); do
array+=("$i")
done
echo "${array[@]}"
