Java 参数不作为命名参数存在

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/24322073/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-08-14 11:32:11  来源:igfitidea点击:

Parameter does not exist as a named parameter

javahibernate

提问by AJ.

My query is like this:

我的查询是这样的:

Query query1 = session.createQuery("select c.email from Contact c where c.contactNo =:contactNo");
    query1.setInteger("contactNo", 22);

The error I got is:

我得到的错误是:

Exception in thread "main" java.lang.IllegalArgumentException: Parameter contactNo does not exist as a named parameter in [select c.email from Contact c where c.contactNo = ?]

线程“main”中的异常 java.lang.IllegalArgumentException:参数 contactNo 作为命名参数不存在 [select c.email from Contact c where c.contactNo = ?]

It is working fine with

它工作正常

Query query = session.createQuery("select c.email from Contact c where c.contactNo = ?");
    query.setInteger(0, 22);

Why 1st query is not working?

为什么第一个查询不起作用?

回答by michikot

Query query1 = session.createQuery("select c.email from Contact c where c.contactNo =:contactNo");
query.setParameter("contactNo", 22);

try using setParameter instead of setInteger

尝试使用 setParameter 而不是 setInteger

回答by RemyG

I think you may need a space before your parameter:

我认为您的参数前可能需要一个空格:

Query query1 = session.createQuery("select c.email from Contact c where c.contactNo = :contactNo");
query.setInteger("contactNo", 22);