scala 为什么我会从这段代码中得到 MalformedInputException？

Why do I get a MalformedInputException from this code?

提问by loloof64

I'm a newbie in Scala, and I wanted to write some sourcecodes from myself for me to get better. I've written a simple object (with a main entry) in order to simulate a "grep" call on all files of the current directory. (I launch the program from Eclipse Indigo, and in Debian Squeeze) :

我是 Scala 的新手，我想自己写一些源代码让我变得更好。我编写了一个简单的对象（带有一个主条目）以模拟对当前目录的所有文件的“grep”调用。（我从 Eclipse Indigo 和 Debian Squeeze 启动程序）：

package com.gmail.bernabe.laurent.scala.tests

import java.io.File

import scala.io.Source

object DealWithFiles {

  def main(args:Array[String]){
    for (result <- grepFilesHere(".*aur.*"))
      println(result)
  }

  private def grepFilesHere(pattern:String):Array[String] = {
    val filesHere = new File(".").listFiles

    def linesOfFile(file:File) =
      Source.fromFile(file).getLines.toList

    for (file <- filesHere;
        if file.isFile
    )
      yield linesOfFile(file)(0)
  }

}

But I get a java.nio.charset.MalformedInputException, which I am not able to solve :

但我得到一个 java.nio.charset.MalformedInputException，我无法解决：

Exception in thread "main" java.nio.charset.MalformedInputException: Input length = 1
at java.nio.charset.CoderResult.throwException(CoderResult.java:260)
at sun.nio.cs.StreamDecoder.implRead(StreamDecoder.java:319)
at sun.nio.cs.StreamDecoder.read(StreamDecoder.java:158)
at java.io.InputStreamReader.read(InputStreamReader.java:167)
at java.io.BufferedReader.fill(BufferedReader.java:136)
at java.io.BufferedReader.readLine(BufferedReader.java:299)
at java.io.BufferedReader.readLine(BufferedReader.java:362)
at scala.io.BufferedSource$BufferedLineIterator.hasNext(BufferedSource.scala:67)
at scala.collection.Iterator$class.foreach(Iterator.scala:772)
at scala.io.BufferedSource$BufferedLineIterator.foreach(BufferedSource.scala:43)
at scala.collection.generic.Growable$class.$plus$plus$eq(Growable.scala:48)
at scala.collection.mutable.ListBuffer.$plus$plus$eq(ListBuffer.scala:130)
at scala.collection.TraversableOnce$class.toList(TraversableOnce.scala:242)
at scala.io.BufferedSource$BufferedLineIterator.toList(BufferedSource.scala:43)
at com.gmail.bernabe.laurent.scala.tests.DealWithFiles$.linesOfFile(DealWithFiles.scala:18)
at com.gmail.bernabe.laurent.scala.tests.DealWithFiles$$anonfun$grepFilesHere.apply(DealWithFiles.scala:23)
at com.gmail.bernabe.laurent.scala.tests.DealWithFiles$$anonfun$grepFilesHere.apply(DealWithFiles.scala:20)
at scala.collection.TraversableLike$WithFilter$$anonfun$map.apply(TraversableLike.scala:697)
at scala.collection.IndexedSeqOptimized$class.foreach(IndexedSeqOptimized.scala:34)
at scala.collection.mutable.ArrayOps.foreach(ArrayOps.scala:38)
at scala.collection.TraversableLike$WithFilter.map(TraversableLike.scala:696)   
at com.gmail.bernabe.laurent.scala.tests.DealWithFiles$.grepFilesHere(DealWithFiles.scala:20)
at com.gmail.bernabe.laurent.scala.tests.DealWithFiles$.main(DealWithFiles.scala:10)
at com.gmail.bernabe.laurent.scala.tests.DealWithFiles.main(DealWithFiles.scala)

Thanks in advance for helps :)

在此先感谢您的帮助:)

回答by Prince John Wesley

From the JavaDoc:

来自 JavaDoc：

MalformedInputExceptionthrown when an input byte sequence is not legal for given charset, or an input character sequence is not a legal sixteen-bit Unicode sequence.

当输入字节序列对于给定字符集不合法，或者输入字符序列不是合法的 16 位 Unicode 序列时，抛出MalformedInputException。

Pass the currect encoding as parameter to Source.fromFilemethod.

将当前编码作为参数传递给Source.fromFile方法。

回答by Madhu

You can handle this character encoding exception by adding below snippet in your code

您可以通过在代码中添加以下代码段来处理此字符编码异常

import scala.io.Codec
import java.nio.charset.CodingErrorAction


implicit val codec = Codec("UTF-8")
codec.onMalformedInput(CodingErrorAction.REPLACE)
codec.onUnmappableCharacter(CodingErrorAction.REPLACE)