bash 如何对“s3cmd ls”的输出进行排序
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How to sort output of "s3cmd ls"
提问by dba.in.ua
Amazon "s3cmd ls" takes like this output:
亚马逊“s3cmd ls”需要这样的输出：
2010-02-20 21:01 1458414588 s3://file1.tgz.00<br>
2010-02-20 21:10 1458414527 s3://file1.tgz.01<br>
2010-02-20 22:01 1458414588 s3://file2.tgz.00<br>
2010-02-20 23:10 1458414527 s3://file2.tgz.01<br>
2010-02-20 23:20 1458414588 s3://file2.tgz.02<br>
<br>
How to select all files of archive, ending at 00 ... XX, with the latest date of fileset ?
如何选择存档的所有文件，以 00 ... XX 结尾，文件集的最新日期？
Date and time is not sorted.
日期和时间未排序。
Bash, regexp ?
Bash，正则表达式？
Thanx!
谢谢！
采纳答案by user unknown
DATE=$(s3cmd ls | sort -n | tail -n 1 | awk '{print }')
s3cmd ls | grep $DATE
sorting as a number schould put youngest dates last. Tail -n1 takes the last line, awk cuts the first word which is the date. Use that to get all entries of that date.
按数字排序应该把最年轻的日期放在最后。tail -n1 取最后一行，awk 剪切第一个单词，即日期。使用它来获取该日期的所有条目。
But maybe I didn't understand the question - so you have to rephrase it. You tell us 'date and time is not sorted' and provide an example where they are sorted - you ask for the latest date, but all entries have the same date.
但也许我不明白这个问题 - 所以你必须改写它。您告诉我们“日期和时间未排序”并提供一个排序示例 - 您要求最新日期，但所有条目都具有相同的日期。
回答by Erik Kristensen
s3cmd ls s3://bucket/path/ | sort -k1,2
This will sort by date ascending.
这将按日期升序排序。
回答by Javeed Shakeel
Try
尝试
This command syntax is s3 ls s3:// path of the bucket / files| sort
此命令语法为s3 ls s3:// 存储桶路径 / 文件| 种类
s3cmd ls s3://file1.tgz.00<br> | sort
It will sort in the descending date at last
它将最后按降序排列
