将自纪元以来的秒数转换为 Scala 中的 joda DateTime
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Convert seconds since epoch to joda DateTime in Scala
提问by randombits
I am attempting to take seconds since epoch and turn it into a DateTime object in Scala. I am use joda. Unfortunately whether I use seconds or milliseconds, I'm getting weird results. What am I doing wrong here?
我试图从纪元开始花几秒钟的时间并将其转换为 Scala 中的 DateTime 对象。我正在使用乔达。不幸的是，无论我使用秒还是毫秒，我都会得到奇怪的结果。我在这里做错了什么？
scala> new org.joda.time.DateTime(1378607203*1000)
res2: org.joda.time.DateTime = 1969-12-31T02:31:40.984Z
scala> new org.joda.time.DateTime(1378607203)
res3: org.joda.time.DateTime = 1970-01-16T22:56:47.203Z
回答by pedrofurla
Check a quick REPL session:
检查快速 REPL 会话：
scala> 1378607203 * 1000
res6: Int = -77299016
Odd, isn't it? :) Can you guess why this is happening?
很奇怪，不是吗？:) 你能猜出为什么会这样吗？
I will give you a hint extracted from DateTime's constructor you are trying to use.
我会给你一个从DateTime你试图使用的构造函数中提取的提示。
DateTime(long instant)
Still don't get it? Let's try a slightly different version:
还是不明白？让我们尝试一个稍微不同的版本：
scala> 1378607203L * 1000
res8: Long = 1378607203000
Notice the Lindicating a literal of type Long. You are asking for 1 trillion! And Int only go as far as 2 billons:
请注意L指示 Long 类型的文字。你要1万亿！而 Int 最多只能达到 20 亿：
scala> Int.MaxValue
res7: Int = 2147483647
So doing DateTime(1378607203L*1000)will make it work.
所以这样做DateTime(1378607203L*1000)会让它起作用。
