如何在 bash shell 脚本变量中查找子字符串
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how to Find a substring in a bash shell script variable
提问by Boby
I have a variable like below.
我有一个像下面这样的变量。
variable = This script is not found
if [[ "$variable" = ~ "not found" ]];
then
echo "Not Found"
else
echo "Its there"
if
while executing im getting below err,
在执行时我低于错误，
line 4: syntax error in conditional expression
./test.sh: line 4: syntax error near `found"'
./test.sh: line 4: `if [[ "$variable" = ~ "not found" ]]; '
could anyone point me, What im missing here?
谁能指出我，我在这里缺少什么？
回答by Quentin Perez
LIST="some string with a substring you want to match"
SOURCE="substring"
if echo "$LIST" | grep -q "$SOURCE"; then
echo "matched";
else
echo "no match";
fi
Good Luck ;)
祝你好运 ;）
回答by William
Compare this with your version at the indicated points:
将此与您在指定点的版本进行比较：
variable="This script is not found" # <--
if [[ "$variable" =~ "not found" ]] # <--
then
echo "Not Found"
else
echo "Its there"
fi # <--
You can't put spaces around = in an assignment, and you need to quote a string literal that has spaces. You don't need a trailing ; if you're going to put then on its own line. And an if-then ends with "fi" not "if".
您不能在赋值中在 = 周围放置空格，并且您需要引用包含空格的字符串文字。你不需要尾随；如果你打算把那么放在它自己的行上。if-then 以“fi”而不是“if”结尾。
回答by jfelipesp
here is a correct construction of your if statement
这是您的 if 语句的正确构造
if [[ "$variable" =~ "not found" ]]; then
echo "Not Found";
else
echo "Its there";
fi
回答by Aryan
I have tried below codes which always return same result either in true or false
我试过下面的代码，它们总是以真或假返回相同的结果
if [[ "$variable" =~ "not found" ]]; then
echo "Not Found";
else
echo "Its there";
fi
